标签:multi The include size output empty can stream void
Return any binary tree that matches the given preorder and postorder traversals.
Values in the traversals pre
and post
are distinct positive integers.
Example 1:
Input: pre = [1,2,4,5,3,6,7], post = [4,5,2,6,7,3,1]
Output: [1,2,3,4,5,6,7]
Note:
1 <= pre.length == post.length <= 30
pre[]
and post[]
are both permutations of 1, 2, ..., pre.length
.Runtime: 8 ms, faster than 98.12% of C++ online submissions for Construct Binary Tree from Preorder and Postorder Traversal.
#include<stdlib.h> #include<vector> #include<stack> #include<queue> #include <iostream> using namespace std; //Definition for a binary tree node. struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: TreeNode *constructFromPrePost(vector<int> &pre, vector<int> &post) { if (pre.size() == 0) return nullptr; stack<TreeNode *> st; TreeNode *root = new TreeNode(pre[0]); st.push(root); int j = 0; int i = 0; TreeNode *node = nullptr; for(int i=1;i<pre.size();++i){ while (st.top()->val == post[j]) { node = st.top(); st.pop(); printf("pop %d\n",node->val); if (st.top()->left == nullptr) { st.top()->left = node; printf("%d left child is %d\n", st.top()->val, node->val); } else { st.top()->right = node; printf("%d right child is %d\n", st.top()->val, node->val); } j++; printf("j: %d\n",j); } if (i < pre.size()){ st.push(new TreeNode(pre[i])); printf("push %d\n",pre[i]); } } while (true) { node = st.top(); st.pop(); if(st.empty()) break; printf("pop %d\n",node->val); if (st.top()->left == nullptr) { st.top()->left = node; printf("%d left child is %d\n", st.top()->val, node->val); } else { st.top()->right = node; printf("%d right child is %d\n", st.top()->val, node->val); } j++; printf("j: %d\n",j); } return root; // printf("return\n"); // printf("root->value %d\n",root->val); // return root; } }; void show_tree(TreeNode *root) { if (root == nullptr) { cout<<"root is nullptr"<<endl; return; } cout<<"root is not nullptr"<<endl; queue<TreeNode *> qu; qu.push(root); int sz; while (!qu.empty()) { sz = qu.size(); TreeNode* node= nullptr; for (int i = 0; i < sz; ++i) { node=qu.front(); cout << node->val << " "; qu.pop(); if (node->left) qu.push(node->left); if (node->right) qu.push(node->right); } cout << "\n"; } } int main() { vector<int> pre{1, 2, 4, 5, 3, 6, 7}; vector<int> post{4, 5, 2, 6, 7, 3, 1}; Solution solution; TreeNode *res = solution.constructFromPrePost(pre, post); // solution.constructFromPrePost(pre, post); printf("res value %d\n",res->val); show_tree(res); return 0; }
提交代码
class Solution { public: TreeNode *constructFromPrePost(vector<int> &pre, vector<int> &post) { if (pre.size() == 0) return nullptr; stack<TreeNode *> st; TreeNode *root = new TreeNode(pre[0]); st.push(root); int j = 0; TreeNode *node = nullptr; for(int i=1;i<=pre.size();++i){ while (st.top()->val == post[j]) { node = st.top(); st.pop(); //printf("pop %d\n",node->val); if(st.empty()) return root; if (st.top()->left == nullptr) { st.top()->left = node; //printf("%d left child is %d\n", st.top()->val, node->val); } else { st.top()->right = node; //printf("%d right child is %d\n", st.top()->val, node->val); } j++; //printf("j: %d\n",j); } if (i < pre.size()){ st.push(new TreeNode(pre[i])); //printf("push %d\n",pre[i]); } } } };
889.Construct Binary Tree from Preorder and Postorder Traversal
标签:multi The include size output empty can stream void
原文地址:https://www.cnblogs.com/learning-c/p/9847610.html