码迷,mamicode.com
首页 > 其他好文 > 详细

bzoj4003

时间:2018-10-27 21:04:54      阅读:140      评论:0      收藏:0      [点我收藏+]

标签:merge   int   ++   const   eof   fread   ret   wap   char   

用左偏树不断向上维护仍在[浴血奋战的]骑士攻击力,不断维护tag维护即可

#include<cstdio>
#include<cctype>
#define ml(x) tr[x].ml
#define ad(x) tr[x].ad
#define ls(x) tr[x].l
#define rs(x) tr[x].r
#define vl(x) tr[x].val
inline char nc(){
    static char buf[100000],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
}
#define M 500000
typedef long long ll;
const int N=3e5+5;
template<class T>inline void read(T &x){
    char ch=nc();x=0;ll f=1;
    for(;!isdigit(ch);ch=nc())if(ch=='-')f=-1;
    for(;isdigit(ch);ch=nc())x=(x<<1)+(x<<3)+ch-'0';
    x*=f;
}
int a[N];
int n,m,cnt,c[N],rt[N],dep[N],head[N],nex[N],to[N],s[N],ans[N];
ll h[N],v[N];
struct data{int dis,l,r;ll ml,ad,val;}tr[N];
inline void swap(int &x,int &y){int tmp=x;x=y,y=tmp;}
inline void addedge(int u,int v){
    nex[++cnt]=head[u],head[u]=cnt,to[cnt]=v;
}
inline void pushdown(int x){
    if(ls(x))vl(ls(x))=vl(ls(x))*ml(x)+ad(x),ml(ls(x))*=ml(x),ad(ls(x))=ad(ls(x))*ml(x)+ad(x);
    if(rs(x))vl(rs(x))=vl(rs(x))*ml(x)+ad(x),ml(rs(x))*=ml(x),ad(rs(x))=ad(rs(x))*ml(x)+ad(x);
    ml(x)=1,ad(x)=0;
}
inline int merge(int x,int y){
    if(!x||!y)return x+y;
    pushdown(x),pushdown(y);
    if(vl(x)>vl(y))swap(x,y);
    rs(x)=merge(rs(x),y);
    if(tr[ls(x)].dis<tr[rs(x)].dis)swap(ls(x),rs(x));
    tr[x].dis=tr[ls(x)].dis+1;
    return x;
}
inline void dfs(int x){
    for(int t,i=head[x];i;i=nex[i]){
        t=to[i],dep[t]=dep[x]+1,dfs(t);
        if(!a[t])vl(rt[t])+=v[t],ad(rt[t])+=v[t];
        else vl(rt[t])*=v[t],ad(rt[t])*=v[t],ml(rt[t])*=v[t];
        rt[x]=merge(rt[x],rt[t]);
    }
    while(rt[x]&&vl(rt[x])<h[x])ans[rt[x]]=x,pushdown(rt[x]),s[x]++,rt[x]=merge(ls(rt[x]),rs(rt[x]));
}
inline void write(int x){
    if(x<10)putchar(x+'0');
    else write(x/10),putchar((x%10)+'0');
}
int main(){
    read(n),read(m),dep[0]=-1;;
    for(int i=1;i<=n;i++)read(h[i]);
    for(int x,i=2;i<=n;i++)read(x),addedge(x,i),read(a[i]),read(v[i]);
    for(int i=1;i<=m;i++){
        read(tr[i].val),read(c[i]),tr[i].ml=1;
        rt[c[i]]=merge(rt[c[i]],i);
    }
    dfs(1);
    for(int i=1;i<=n;i++)write(s[i]),puts("");
    for(int i=1;i<=m;i++)write(dep[c[i]]-dep[ans[i]]),puts("");
    return 0;
}

bzoj4003

标签:merge   int   ++   const   eof   fread   ret   wap   char   

原文地址:https://www.cnblogs.com/MikuKnight/p/9863073.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!