码迷,mamicode.com
首页 > 其他好文 > 详细

240. Search a 2D Matrix II

时间:2018-11-03 16:28:13      阅读:210      评论:0      收藏:0      [点我收藏+]

标签:ssi   targe   font   ret   prope   integer   ++i   cto   mis   

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
Example:

Consider the following matrix:

[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]]
Given target = 5, return true.

Given target = 20, return false.

Approach #1 Using binary search in each column.

class Solution {
public:
    bool searchMatrix(vector<vector<int>>& matrix, int target) {
        int len1 = matrix.size();
        if (len1 == 0) return false;
        int len2 = matrix[0].size();
        if (len2 == 0) return false;
        for (int i = 0; i < len1; ++i) {
            auto it = lower_bound(matrix[i].begin(), matrix[i].end(), target);
            if (it < matrix[i].end() && *it == target) return true;
        }
        return false;
    }
};


Runtime: 88 ms, faster than 23.74% of C++ online submissions for Search a 2D Matrix II.

Approach #2

class Solution {
public:
    bool searchMatrix(vector<vector<int>>& matrix, int target) {
        int m = matrix.size();
        if (m == 0) return false;
        int n = matrix[0].size();
        int i = 0, j = n - 1;
        for (; i < m && j >= 0; ) {
            if (matrix[i][j] == target) return true;
            else if (matrix[i][j] > target) j--;
            else i++;
        }
        return false;
    }
};

Runtime: 52 ms, faster than 55.98% of C++ online submissions for Search a 2D Matrix II.

240. Search a 2D Matrix II

标签:ssi   targe   font   ret   prope   integer   ++i   cto   mis   

原文地址:https://www.cnblogs.com/ruruozhenhao/p/9900956.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!