标签:style http color io os ar for sp on
直接用字符串去比较即可,先判断原数字正确不正确,然后写一个判断函数,注意细节,然后注意判掉空串情况
代码:
#include <cstdio>
#include <cstring>
const int N = 105;
char n[N], a[N], b[N];
bool judge(char *str) {
int len = strlen(str);
if (len == 0) return false;
int s = 0;
if (str[s] == '-') {
if (len == 1) return false;
s++;
}
if (len != 1 && str[s] == '0') return false;
for (int i = s; i < len; i++) {
if (str[i] < '0' || str[i] > '9')
return false;
}
return true;
}
bool big(char *a, char *b) {
if (a[0] == '-' && b[0] != '-') return false;
if (a[0] != '-' && b[0] == '-') return true;
int i = 0, j = 0;
int lena = strlen(a), lenb = strlen(b);
bool flag = true;
if (a[i] == '-' && b[j] == '-') {
i++; j++;
flag = false;
}
if (lena > lenb) return flag;
if (lena < lenb) return !flag;
while (i < lena && j < lenb) {
if (a[i] > b[j]) return flag;
else if (a[i] < b[j]) return !flag;
i++; j++;
}
return true;
}
bool solve() {
if (!judge(n)) return false;
if (big(n, a) && big(b, n)) return true;
return false;
}
int main() {
while (gets(n) != NULL) {
scanf("%s%s%*c", a, b);
while (!judge(a) || !judge(b));
printf("%s\n", solve() ? "YES" : "NO");
}
return 0;
}标签:style http color io os ar for sp on
原文地址:http://blog.csdn.net/accelerator_/article/details/40002301