1 Maximum Product Subarray_Leetcode

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Find the contiguous subarray within an array (containing at least one number) which has the largest product.

For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest product = 6.

Since two negative numbers may multiply and get a large number, I need to track the minimum number of each position in the sequence.

At each point, the maximum can be obtained by three numbers:

1. A[i]

2. A[i] * curmax

3. A[i] * curmin

Similar as the minimum update.

FIRST TRY ERROR:

I should use temp variable to store the curmax, since the update of curmin use the previous value of curmax.

Code:

class Solution {
public:
    int maxProduct(int A[], int n) {
        if(n == 0 || A == NULL) return 0;
        int curmax = A[0], curmin = A[0];
        int res = A[0];
        
        for(int i = 1; i < n; i++)
        {
            int tmpmax = curmax, tmpmin = curmin;   // take care, curmax is used when calc curmin, so do not update
            curmax = max(max(A[i], A[i]*tmpmax), A[i]*tmpmin);
            curmin = min(min(A[i], A[i]*tmpmax), A[i]*tmpmin);
            if(curmax > res) res = curmax;
        }
        return res;
    }
};

1 Maximum Product Subarray_Leetcode

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原文地址：http://www.cnblogs.com/avril/p/4020557.html