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leetcode dfs Validate Binary Search Tree

时间:2014-10-12 17:40:38      阅读:180      评论:0      收藏:0      [点我收藏+]

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Validate Binary Search Tree

 Total Accepted: 23828 Total Submissions: 91943My Submissions

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

题意:给定一棵二叉树,判断它是不是合法的二叉查找树
思路:dfs
合法二叉查找树必须满足以下两个条件
1.左子树和右子树都是合法二叉查找树
2.左子树的最右叶子节点 < 根 < 右子树的最左叶子节点
复杂度:时间O(n),空间O(log n)


bool isValidBST(TreeNode *root) {
	if(!root) return true;
	TreeNode *right_most = root->left, *left_most = root->right;
	while(right_most && right_most->right){
		right_most = right_most->right;
	}
	while(left_most && left_most->left){
		left_most = left_most->left;
	}
	return isValidBST(root->left) && isValidBST(root->right)
		&& (!right_most || right_most->val < root->val)
		&& (!left_most || root->val < left_most->val);
}



leetcode dfs Validate Binary Search Tree

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原文地址:http://blog.csdn.net/zhengsenlie/article/details/40018467

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