标签:with += china height gre def 最小割 ble %s
Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 673 Accepted Submission(s): 400
#include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <cctype> #include <set> #include <vector> #include <stack> #include <queue> #include <algorithm> #include <cmath> #include <bitset> #define rap(i, a, n) for(int i=a; i<=n; i++) #define rep(i, a, n) for(int i=a; i<n; i++) #define lap(i, a, n) for(int i=n; i>=a; i--) #define lep(i, a, n) for(int i=n; i>a; i--) #define rd(a) scanf("%d", &a) #define rlld(a) scanf("%lld", &a) #define rc(a) scanf("%c", &a) #define rs(a) scanf("%s", a) #define rb(a) scanf("%lf", &a) #define rf(a) scanf("%f", &a) #define pd(a) printf("%d\n", a) #define plld(a) printf("%lld\n", a) #define pc(a) printf("%c\n", a) #define ps(a) printf("%s\n", a) #define MOD 2018 #define LL long long #define ULL unsigned long long #define Pair pair<int, int> #define mem(a, b) memset(a, b, sizeof(a)) #define _ ios_base::sync_with_stdio(0),cin.tie(0) //freopen("1.txt", "r", stdin); using namespace std; const int maxn = 1e5 + 10, INF = 0x7fffffff; int dir[4][2] = {{1, 0},{-1, 0},{0, 1},{0, -1}}; int n, m, G, S, s, t; int head[maxn], cur[maxn], d[maxn], vis[maxn], nex[maxn << 1], cnt; struct node { int u, v, c; }Node[maxn << 1]; void add_(int u, int v, int c) { Node[cnt].u = u; Node[cnt].v = v; Node[cnt].c = c; nex[cnt] = head[u]; head[u] = cnt++; } void add(int u, int v, int c) { add_(u, v, c); add_(v, u, 0); } bool bfs() { mem(d, 0); queue<int> Q; d[s] = 1; Q.push(s); while(!Q.empty()) { int u = Q.front(); Q.pop(); for(int i = head[u]; i != -1; i = nex[i]) { int v = Node[i].v; if(!d[v] && Node[i].c > 0) { d[v] = d[u] + 1; Q.push(v); if(v == t) return 1; } } } return d[t] != 0; } int dfs(int u, int cap) { int ret = 0; if(u == t || cap == 0) return cap; for(int &i = cur[u]; i != -1; i = nex[i]) { int v = Node[i].v; if(d[v] == d[u] + 1 && Node[i].c > 0) { int V = dfs(v, min(cap, Node[i].c)); Node[i].c -= V; Node[i ^ 1].c += V; ret += V; cap -= V; if(cap == 0) break; } } if(cap > 0) d[u] = -1; return ret; } int Dinic() { int ans = 0; while(bfs()) { memcpy(cur, head, sizeof(head)); ans += dfs(s, INF); } return ans; } int main() { int T, kase = 0; rd(T); while(T--) { mem(head, -1); cnt = 0; int w; rd(n), rd(m), rd(G), rd(S); s = 0, t = n * m * 2 + 10; int sum = 0; rap(i, 1, n) { rap(j, 1, m) { rep(k, 0, 4) { int nx = i + dir[k][0]; int ny = j + dir[k][1]; if(nx < 1 || ny < 1 || nx > n || ny > m) continue; add((i - 1) * m + j, n * m + (nx - 1) * m + ny, (((i + j) & 1) ? G : S)); } rd(w); sum += w; if((i + j) & 1) add(s, (i - 1) * m + j, w); else add(n * m + (i - 1) * m + j, t, w); add((i - 1) * m + j, n * m + (i - 1) * m + j, INF); } } rap(i, 1, n) rap(j, 1, m) { rd(w); sum += w; if((i + j) & 1) add(n * m + (i - 1) * m + j, t, w); else add(s, (i - 1) * m + j, w); } printf("Case %d: ", ++kase); cout << sum - Dinic() << endl; } return 0; }
Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 673 Accepted Submission(s): 400
标签:with += china height gre def 最小割 ble %s
原文地址:https://www.cnblogs.com/WTSRUVF/p/9973566.html