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#Leetcode# 4. Median of Two Sorted Arrays

时间:2018-11-21 16:19:30      阅读:130      评论:0      收藏:0      [点我收藏+]

标签:ted   cti   median   cannot   EDA   not   log   sorted   com   

https://leetcode.com/problems/median-of-two-sorted-arrays/

 

There are two sorted arrays nums1 and nums2 of size m and n respectively.

Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).

You may assume nums1 and nums2 cannot be both empty.

Example 1:

nums1 = [1, 3]
nums2 = [2]

The median is 2.0

Example 2:

nums1 = [1, 2]
nums2 = [3, 4]

The median is (2 + 3)/2 = 2.5

代码:

class Solution {
public:
    double findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) {
        vector<int> v;
        for(int i = 0; i < nums1.size(); i ++)
            v.push_back(nums1[i]);
        for(int i = 0; i < nums2.size(); i ++)
            v.push_back(nums2[i]);
        
        sort(v.begin(), v.end());
        double ans = 0.0;
        if(v.size() % 2 == 0)
            ans = 1.0 * (v[v.size() / 2 - 1] + v[v.size() / 2 + 1 - 1]) / 2;
        else ans = 1.0 * v[(v.size() + 1) / 2 - 1];
        
        return ans;
    }
};

 

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第一道 hard 题目 嘻嘻嘻

#Leetcode# 4. Median of Two Sorted Arrays

标签:ted   cti   median   cannot   EDA   not   log   sorted   com   

原文地址:https://www.cnblogs.com/zlrrrr/p/9994181.html

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