标签:++ back 输入 color als turn oar ble ref
题目描述和代码参考:https://www.geeksforgeeks.org/8-queen-problem/
NQueenProblem(js代码):
class NQueenProblem { static printSolution(board, numOfSolutions) { console.log(`第${numOfSolutions}种解法:`); for (let i = 0; i != board.length; ++i) { let temp = ""; for (let j = 0; j != board.length; ++j) { temp += board[i][j] + " "; } console.log(temp); } } static solve(num) { let numOfSolutions = 0; let board = CommonUtil.zeros(num, num); let isSafe = function(col, row) { // 检查该行左边有没皇后 for (let i = 0; i != col; ++i) { if (board[i][row] == 1) return false; } // 检查左上角 for (let i = col - 1, j = row - 1; i >= 0 && j >= 0; --i, --j) { if (board[i][j] == 1) return false; } // 检查左下角 for (let i = col - 1, j = row + 1; i >= 0 && j < num; --i, ++j) { if (board[i][j] == 1) return false; } return true; }; let placeNextQueen = function(col) { // 如果所有皇后都放置好了,说明找到了一种方案 if (col >= num) { NQueenProblem.printSolution(board, ++numOfSolutions); return; } // 在可以放的地方试探 for (let i = 0; i != num; ++i) { if (isSafe(col, i)) { board[col][i] = 1; placeNextQueen(col + 1); board[col][i] = 0; } } }; placeNextQueen(0); } static run(data) { NQueenProblem.solve(Number(data)); // Number(data)指的是皇后的数量 } }
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mColoringProblem(js代码):
class mColoringProblem { static printSolution(colorOfPoint, numOfSolutions) { console.log(`第${numOfSolutions}种解法:`); console.log(colorOfPoint); // 例如输出[1, 2, 3, 4, 1],表示第1个点第1种颜色, // 表示第2个点第2种颜色,表示第3个点第3种颜色, // 表示第4个点第4种颜色,表示第5个点第1种颜色, } static solve(graph, m) { let numOfSolutions = 0; let colorOfPoint = graph.map(() => 0); // 存储每个点的着色情况 let isSafe = function(pointId, colorId) { // 检查会不会和相邻的已着色点冲突 for (let i = 0; i != pointId; ++i) { if (graph[pointId][i] == 1 && colorId == colorOfPoint[i]) { return false; } } return true; }; let coloringNext = function(pointId) { // 如果所有点都已经着色,说明找到了一种方案 if (pointId >= graph.length) { mColoringProblem.printSolution(colorOfPoint, ++numOfSolutions); return; } // 尝试着色 for (let i = 1; i <= m; ++i) { if (isSafe(pointId, i)) { colorOfPoint[pointId] = i; coloringNext(pointId + 1); colorOfPoint[pointId] = 0; } } }; coloringNext(0); } static run(data) { // 输入格式:首个数字表示着色点个数 // 之后是一个描述无向图的邻接矩阵, // 最后是颜色数量 data = CommonUtil.handleData(data); let num = data[0]; let graph = CommonUtil.zeros(num, num); let k = 0; for (let i = 0; i != num; ++i) { for (let j = 0; j != num; ++j) { graph[i][j] = data[++k]; } } let m = data[k + 1]; // console.log(num, graph, m); mColoringProblem.solve(graph, m); } }
标签:++ back 输入 color als turn oar ble ref
原文地址:https://www.cnblogs.com/xkxf/p/9998247.html