标签:false \n cin can style 判断 ace clu cout
用的dfs,自下往上搜索一个节点的所有祖先,然后在相应祖先 判断是否是另一个节点的祖先,如果是 就截止,否则继续往上搜索,直到搜索到,或者知道所有的祖先都被扫描完成
#include <bits/stdc++.h> using namespace std; const int N = 1e3+10; int n; int cnt, tot; map<string ,int> mp; string s[N]; vector<int> son[N], fa[N]; string s1, s2; int getId(string str) { if(mp[str]) { return mp[str]; } mp[str] = (++cnt); s[cnt] = str; return cnt; } int dfs(int u, int v) { if(u == v) return true; for(int i=0; i<son[u].size(); i++) { int x = son[u][i]; //cout << s[x] <<" "; if(dfs(son[u][i], v)) { return true; } } //cout<<"\n"; return false; } int main() { freopen("in.txt","r",stdin); scanf("%d", &n); for(int i=1; i<=n; i++) { cin >> s1 >> s2; int u = getId(s1); int v = getId(s2); son[u].push_back(v); fa[v].push_back(u); } int m; scanf("%d",&m); while(m--) { cin >> s1 >> s2; int u = getId(s1); int v = getId(s2); // cout <<u <<" "<< v<<"\n"; bool flag=0; queue<int> que; que.push(u); while(!que.empty()) { int tmp=que.front(); que.pop(); //cout << s[tmp]<<"\n"; for(int i=0; i<fa[tmp].size(); i++) { que.push(fa[tmp][i]); } if(dfs(tmp,v)) { flag = true; cout << s[tmp] <<endl; break; } } if(!flag) puts("-1"); } return 0; }
标签:false \n cin can style 判断 ace clu cout
原文地址:https://www.cnblogs.com/Draymonder/p/10007484.html