标签:判断 and gfs bytes ati for font number oid
public class LetterAndNumberCount {
public static void main(String[] args) {
Count("FJJgjsgfsd543632");
count1("SFsefgdg2354354fsdf");
}
public static void Count(String str){
int A = 0;
int a = 0;
int Number = 0;
byte[] bytes = str.getBytes(); // 将字符串转为byte数组
for(int i=0;i<bytes.length;i++){
if(bytes[i] >= ‘a‘ && bytes[i] <= ‘z‘){
a++;
}else if(bytes[i]>=‘A‘ && bytes[i]<=‘Z‘){
A++;
}else if(bytes[i]>=‘0‘ && bytes[i]<=‘9‘){
Number++;
}
}
System.out.println("大写字母个数为:"+ A);
System.out.println("小写字母个数为:"+ a);
System.out.println("数字个数为:"+ Number);
}
public static void count1(String str){
int A = 0;
int a = 0;
int Number = 0;
for(int i=0;i<str.length();i++){
char array = str.charAt(i); //便利数组后用charAt(i)来返回指定字符然后if进行判断
if(array >= ‘a‘ && array <= ‘z‘){
a++;
}else if(array>=‘A‘ && array<=‘Z‘){
A++;
}else if(array>=‘0‘ && array<=‘9‘){
Number++;
}
}
System.out.println("大写字母个数为:"+ A);
System.out.println("小写字母个数为:"+ a);
System.out.println("数字个数为:"+ Number);
}
}
给出字符串分别计算出字符串中数字、大小写字母的个数。(两种方法 getBytes( ) charAt( ) )
标签:判断 and gfs bytes ati for font number oid
原文地址:https://www.cnblogs.com/bigmaxblog/p/10021542.html