#Leetcode# 155. Min Stack

标签：called   remove   注意   support   strong   get   ports   port   两个栈   

https://leetcode.com/problems/min-stack/

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

• push(x) -- Push element x onto stack.
• pop() -- Removes the element on top of the stack.
• top() -- Get the top element.
• getMin() -- Retrieve the minimum element in the stack.

Example:

MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin();   --> Returns -3.
minStack.pop();
minStack.top();      --> Returns 0.
minStack.getMin();   --> Returns -2.

代码：

class MinStack {
public:
    /** initialize your data structure here. */
    MinStack() {}
    
    void push(int x) {
        s1.push(x);
        if (s2.empty() || x <= s2.top()) s2.push(x);
    }
    
    void pop() {
        if (s1.top() == s2.top()) s2.pop();
        s1.pop();
    }
    
    int top() {
        return s1.top();
    }
    
    int getMin() {
        return s2.top();
    }
    
private:
    stack<int> s1, s2;
};
/**
 * Your MinStack object will be instantiated and called as such:
 * MinStack obj = new MinStack();
 * obj.push(x);
 * obj.pop();
 * int param_3 = obj.top();
 * int param_4 = obj.getMin();
 */

　　用两个栈来存 $s2$ 用来存最小的 第一次写这样的题 不是很会看了题解才知道怎么写 下次注意！

#Leetcode# 155. Min Stack

标签：called   remove   注意   support   strong   get   ports   port   两个栈   

原文地址：https://www.cnblogs.com/zlrrrr/p/10037218.html