350. Intersection of Two Arrays II

标签：def   accept   +=   write   cti   sel   and   self   inter   

Given two arrays, write a function to compute their intersection.

Example 1:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]

Example 2:

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [4,9]

Note:

• Each element in the result should appear as many times as it shows in both arrays.
• The result can be in any order.

Follow up:

• What if the given array is already sorted? How would you optimize your algorithm?
• What if nums1‘s size is small compared to nums2‘s size? Which algorithm is better?
• What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?

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class Solution:
    def intersect(self, nums1, nums2):
        """
        :type nums1: List[int]
        :type nums2: List[int]
        :rtype: List[int]
        """
        nums1.sort()
        nums2.sort()
        i,j = 0,0
        res = []
        while i<len(nums1) and j<len(nums2):
            if nums1[i]==nums2[j]:
                res.append(nums1[i])
                i += 1
                j += 1
                continue
            if nums1[i]<nums2[j]:
                i += 1
                continue
            j += 1
        return res

350. Intersection of Two Arrays II

标签：def   accept   +=   write   cti   sel   and   self   inter   

原文地址：https://www.cnblogs.com/bernieloveslife/p/10060977.html