标签:nal span code question ++ memset 打印路径 scanf ace
1 #include<bits/stdc++.h> 2 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 3 #pragma GCC optimize(2) 4 5 using namespace std; 6 7 struct Node 8 { 9 int v[3],dist,fa; 10 int from,to; 11 }; 12 13 const int maxn = 200 + 5; 14 int vis[maxn][maxn],cap[3],ans[maxn]; 15 vector<Node> nodes; 16 17 void update_ans(const Node& u) 18 { 19 _for(i,0,3) 20 { 21 int d = u.v[i]; 22 if(ans[d] < 0 || u.dist < ans[d]) ans[d] = u.dist; 23 } 24 } 25 26 struct cmp 27 { 28 bool operator () (const int a,const int b) const 29 { 30 return nodes[a].dist > nodes[b].dist; 31 } 32 }; 33 34 int final = 0; 35 void solve(int a,int b,int c, int &d) 36 { 37 cap[0] = a,cap[1] = b,cap[2] = c; 38 memset(vis,0,sizeof(vis)); 39 memset(ans,-1,sizeof(ans)); 40 nodes.clear(); 41 priority_queue<int,vector<int>,cmp> q; 42 43 Node start; 44 start.dist = 0; 45 //c is full in the begining 46 start.v[0] = 0,start.v[1] = 0,start.v[2] = c,start.fa = 0; 47 start.from = start.to = -1; 48 q.push(0); 49 nodes.push_back(start); 50 51 vis[0][0] = 1; 52 while(!q.empty()) 53 { 54 int u = q.top();q.pop(); 55 update_ans(nodes[u]); 56 if(ans[d] >= 0) {break;} 57 _for(i,0,3)// i.water -> j.water 58 { 59 _for(j,0,3) 60 { 61 // i is j or i is no-water or j is full 62 if(i==j || nodes[u].v[i]==0 || nodes[u].v[j] == cap[j]) continue; 63 //all of i in or a part of i in 64 int amount = min(cap[j],nodes[u].v[i]+nodes[u].v[j]) - nodes[u].v[j]; 65 Node u2; 66 memcpy(&u2,&nodes[u],sizeof(Node)); 67 u2.dist = nodes[u].dist+amount; 68 u2.v[i] -= amount; 69 u2.v[j] += amount; 70 u2.from = i; 71 u2.to = j; 72 if(!vis[u2.v[0]][u2.v[1]]) 73 { 74 vis[u2.v[0]][u2.v[1]] = 1; 75 u2.fa = u; 76 nodes.push_back(u2); 77 q.push(nodes.size()-1); 78 } 79 } 80 } 81 } 82 while(d >= 0) 83 { 84 if(ans[d]>=0) 85 { 86 cout << "minimum water & goal" << endl; 87 printf("%d %d\n\n",ans[d],d); 88 return ; 89 } 90 d --; 91 } 92 } 93 94 void print_ans(int d) 95 { 96 int start; 97 _for(i,0,nodes.size()) 98 { 99 if(ans[d]==nodes[i].dist) {start = i;break;} 100 } 101 vector<vector<int>> rnt; 102 vector<int> tmp; 103 while(start) 104 { 105 tmp.clear(); 106 tmp.push_back(nodes[start].v[0]); 107 tmp.push_back(nodes[start].v[1]); 108 tmp.push_back(nodes[start].v[2]); 109 tmp.push_back(nodes[start].from+1); 110 tmp.push_back(nodes[start].to+1); 111 rnt.push_back(tmp); 112 start = nodes[start].fa; 113 } 114 cout << "Begin:" << endl; 115 cout << nodes[0].v[0] << " " << nodes[0].v[1] << " " << nodes[0].v[2] << endl << endl; 116 for(int i = rnt.size()-1;i >= 0;i --) 117 { 118 cout << rnt[i][3] << "th -> " << rnt[i][4] << "th" << endl; 119 for(int j = 0;j < 3;j ++) 120 { 121 cout << rnt[i][j] << " "; 122 } 123 cout << endl << endl; 124 } 125 cout << "Question solved" << endl << endl << endl << endl; 126 cout << "**********" << endl; 127 } 128 129 int main() 130 { 131 // freopen("Miku.txt","w",stdout); 132 int T,a,b,c,d; 133 scanf("%d",&T); 134 while(T --) 135 { 136 scanf("%d%d%d%d",&a,&b,&c,&d); 137 solve(a,b,c,d); 138 print_ans(d); 139 } 140 return 0; 141 }
可以打印路径,基本上照抄刘汝佳
标签:nal span code question ++ memset 打印路径 scanf ace
原文地址:https://www.cnblogs.com/Asurudo/p/10060930.html