标签:inpu false exp etc example not 规划 solution lse
Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal.
Note:
Each of the array element will not exceed 100.
The array size will not exceed 200.
Example 1:
Input: [1, 5, 11, 5]
Output: true
Explanation: The array can be partitioned as [1, 5, 5] and [11].
Example 2:
Input: [1, 2, 3, 5]
Output: false
Explanation: The array cannot be partitioned into equal sum subsets.
分析
这道题用动态规划,dp[i] 表示是否能从数组中取得数字之和为i , 动态转移方程dp[i]=dp[i]||dp[i-n] .
class Solution {
public:
bool canPartition(vector<int>& nums) {
int s=accumulate(nums.begin(),nums.end(),0);
if(s%2!=0) return false;
vector<int> dp(s/2+1,0);
dp[0]=1;
vector<int> visited(s/2+1,0);
for(auto o:nums)
for(int i=s/2;i>=o;i--)
dp[i]=dp[i-o]||dp[i];
return dp[s/2]==1;
}
};
LeetCode 416. Partition Equal Subset Sum
标签:inpu false exp etc example not 规划 solution lse
原文地址:https://www.cnblogs.com/A-Little-Nut/p/10066934.html