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LeetCode 563. Binary Tree Tilt

时间:2018-12-05 22:55:49      阅读:191      评论:0      收藏:0      [点我收藏+]

标签:tree node   code   leetcode   diff   order   absolute   define   des   not   

Given a binary tree, return the tilt of the whole tree.

The tilt of a tree node is defined as the absolute difference between the sum of all left subtree node values and the sum of all right subtree node values. Null node has tilt 0.

The tilt of the whole tree is defined as the sum of all nodes’ tilt.

Example:

Input: 
         1
       /         2     3
Output: 1
Explanation: 
Tilt of node 2 : 0
Tilt of node 3 : 0
Tilt of node 1 : |2-3| = 1
Tilt of binary tree : 0 + 0 + 1 = 1

Note:

  • The sum of node values in any subtree won’t exceed the range of 32-bit integer.
  • All the tilt values won’t exceed the range of 32-bit integer.
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {// 后序遍历求和
public:
    int postorder(TreeNode* root){
        if(root==NULL) return 0;
        int leftsum=postorder(root->left);
        int rightsum=postorder(root->right);
        sum+=abs(leftsum-rightsum);
        return leftsum+rightsum+root->val;
    }
    int findTilt(TreeNode* root) {
        postorder(root);
        return sum;
    }
private:
    int sum=0;
};

LeetCode 563. Binary Tree Tilt

标签:tree node   code   leetcode   diff   order   absolute   define   des   not   

原文地址:https://www.cnblogs.com/A-Little-Nut/p/10073981.html

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