LeetCode 561. Array Partition I

标签：not   nat   positive   ret   solution   output   ble   leetcode   note   

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]
Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

Note:

• n is a positive integer, which is in the range of [1, 10000].
• All the integers in the array will be in the range of [-10000, 10000].

class Solution {
public:
    int arrayPairSum(vector<int>& nums) {
        int sum=0;
        sort(nums.begin(),nums.end());
        for(int i=nums.size()-2;i>=0;i-=2)
            sum+=nums[i];
        return sum;
            
    }
};

LeetCode 561. Array Partition I

标签：not   nat   positive   ret   solution   output   ble   leetcode   note   

原文地址：https://www.cnblogs.com/A-Little-Nut/p/10073973.html