标签:amp std return printf turn set void har ==
题意:给一棵树,输出树上所有最长路径包含的节点
树的直径的应用
#include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<algorithm> #include<cmath> #define N 200005 #define N2 400005 using namespace std; inline int read() { int f=1,x=0; char ch=getchar(); while(ch<‘0‘ || ch>‘9‘) {if(ch==‘-‘) f=-1; ch=getchar();} while(ch>=‘0‘ && ch<=‘9‘) {x=x*10+ch-‘0‘; ch=getchar();} return x*f; } int n,cnt,ans=-1; int v[N2],head[N],nxt[N2]; int d1[N],d2[N],c[N],w[N]; void add(int x,int y) { v[++cnt]=y; nxt[cnt]=head[x]; head[x]=cnt; } int dfs(int x,int fa) { for(int i=head[x];i!=-1;i=nxt[i]) { int t=v[i]; if(t==fa) continue; int s=dfs(t,x)+1; if(s>d1[x]) { d2[x]=d1[x]; d1[x]=s; c[x]=t; } else if(s>d2[x]) d2[x]=s; } ans=max(ans,d1[x]+d2[x]); return d1[x]; } void dfs2(int x,int fa) { if(x) { if(c[fa]!=x) w[x]=max(w[fa],d1[fa])+1; else w[x]=max(w[fa],d2[fa])+1; } for(int i=head[x];i!=-1;i=nxt[i]) if(v[i]!=fa) dfs2(v[i],x); } int main() { memset(head,-1,sizeof(head));//节点编号从0开始 int i; int x,y; n=read(); for(i=1;i<n;++i) { x=read(); y=read(); add(x,y); add(y,x); } dfs(0,-1); dfs2(0,-1); for(i=0;i<n;i++) if(w[i]+d1[i]==ans || d1[i]+d2[i]==ans) printf("%d\n",i); return 0; }
标签:amp std return printf turn set void har ==
原文地址:https://www.cnblogs.com/llllllpppppp/p/10086505.html