标签:des style blog http color io ar for sp
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ‘s undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neighbor of the node. As an example, consider the serialized graph {0,1,2#1,2#2,2}. The graph has a total of three nodes, and therefore contains three parts as separated by #. First node is labeled as 0. Connect node 0 to both nodes 1 and 2. Second node is labeled as 1. Connect node 1 to node 2. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle. Visually, the graph looks like the following: 1 / / 0 --- 2 / \_/
Leetcode里关于图的题其实并不多,这道题就是其中之一。DFS深度优先搜索和BFS广度优先搜索都可以做,遍历完原图的所有节点。这道题的难点在于neighbour关系的拷贝:原图中某一个点跟一些点具有neighbour关系,那么该点的拷贝也要与上述那些点的拷贝具有neighbour关系。那么,就需要很灵活地通过一个点访问该点的拷贝,最好的办法就是把该点与该点的拷贝存入一个HashMap。这样做还有一个好处,就是帮我们剩下了一个visited数组,我们可以用这个HashMap来知道哪些点我是访问过的。
方法是用BFS做的:
1 /** 2 * Definition for undirected graph. 3 * class UndirectedGraphNode { 4 * int label; 5 * List<UndirectedGraphNode> neighbors; 6 * UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); } 7 * }; 8 */ 9 public class Solution { 10 public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { 11 if (node == null) return null; 12 HashMap<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<UndirectedGraphNode, UndirectedGraphNode>(); 13 LinkedList<UndirectedGraphNode> queue = new LinkedList<UndirectedGraphNode>(); 14 queue.offer(node); 15 UndirectedGraphNode copy = new UndirectedGraphNode(node.label); 16 map.put(node, copy); 17 while (!queue.isEmpty()) { 18 UndirectedGraphNode cur = queue.poll(); 19 for (int i=0; i<cur.neighbors.size(); i++) { 20 if (!map.containsKey(cur.neighbors.get(i))) { 21 queue.offer(cur.neighbors.get(i)); 22 UndirectedGraphNode neighborCopy = new UndirectedGraphNode(cur.neighbors.get(i).label); 23 map.put(cur.neighbors.get(i), neighborCopy); 24 } 25 map.get(cur).neighbors.add(map.get(cur.neighbors.get(i))); 26 } 27 } 28 return map.get(node); 29 } 30 }
网上看了别人的解法:
用Stack写的DFS方法:
1 public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { 2 if(node == null) 3 return null; 4 LinkedList<UndirectedGraphNode> stack = new LinkedList<UndirectedGraphNode>(); 5 HashMap<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<UndirectedGraphNode, UndirectedGraphNode>(); 6 stack.push(node); 7 UndirectedGraphNode copy = new UndirectedGraphNode(node.label); 8 map.put(node,copy); 9 while(!stack.isEmpty()) 10 { 11 UndirectedGraphNode cur = stack.pop(); 12 for(int i=0;i<cur.neighbors.size();i++) 13 { 14 if(!map.containsKey(cur.neighbors.get(i))) 15 { 16 copy = new UndirectedGraphNode(cur.neighbors.get(i).label); 17 map.put(cur.neighbors.get(i),copy); 18 stack.push(cur.neighbors.get(i)); 19 } 20 map.get(cur).neighbors.add(map.get(cur.neighbors.get(i))); 21 } 22 } 23 return map.get(node); 24 }
用Recursion写的DFS方法:
1 public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { 2 if(node == null) 3 return null; 4 HashMap<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<UndirectedGraphNode, UndirectedGraphNode>(); 5 UndirectedGraphNode copy = new UndirectedGraphNode(node.label); 6 map.put(node,copy); 7 helper(node,map); 8 return copy; 9 } 10 private void helper(UndirectedGraphNode node, HashMap<UndirectedGraphNode, UndirectedGraphNode> map) 11 { 12 for(int i=0;i<node.neighbors.size();i++) 13 { 14 UndirectedGraphNode cur = node.neighbors.get(i); 15 if(!map.containsKey(cur)) 16 { 17 UndirectedGraphNode copy = new UndirectedGraphNode(cur.label); 18 map.put(cur,copy); 19 helper(cur,map); 20 } 21 map.get(node).neighbors.add(map.get(cur)); 22 } 23 }
标签:des style blog http color io ar for sp
原文地址:http://www.cnblogs.com/EdwardLiu/p/4023592.html