标签：int 运算符 判断 erro else name print 运算 ror
判断某个东西是否在某个东西里面包含
in not in
name = ‘郑建文‘
if ‘郑文‘ in name:
print(‘ok‘)
else:
print(‘Error‘)
name = ‘郑建文‘
if ‘文‘ not in name:
print(‘1‘)
else:
print(‘2‘)
标签：int 运算符 判断 erro else name print 运算 ror
原文地址：https://www.cnblogs.com/jiangdali/p/10116973.html
