有效的字母异位词的golang实现

输入: s = "anagram", t = "nagaram"
输出: true
输入: s = "rat", t = "car"
输出: false

// 比较两个排好序的字符串是不是一样
func isAnagram(s string, t string) bool {
    var ss []string
    var ts []string
    for _, c := range s {
        ss = append(ss, string(c))
    }
    for _, c := range t {
        ts = append(ts, string(c))
    }
    sort.Strings(ss)
    sort.Strings(ts)
    return reflect.DeepEqual(ss, ts)
    // return stringSliceEqualBCE(ss, ts)
}

func stringSliceEqualBCE(a, b []string) bool {
    if len(a) != len(b) {
        return false
    }

    if (a == nil) != (b == nil) {
        return false
    }

    b = b[:len(a)]
    for i, v := range a {
        if v != b[i] {
            return false
        }
    }

    return true
}

// 用两个字典分别把两个字符串的字符出现个数保存起来
func isAnagram1(s string, t string) bool {
    var sMap = make(map[rune]int)
    var tMap = make(map[rune]int)

    for _, c := range s {
        sMap[c] = sMap[c] + 1
    }
    for _, c := range t {
        tMap[c] = tMap[c] + 1
    }
    return reflect.DeepEqual(sMap, tMap)
}