原文：
1.6 Given an image represented by an NxN matrix, where each pixel in the image is 4 bytes, write a method to rotate the image by 90 degrees. Can you do this in place?
译文：
一张图像表示成NxN的矩阵，图像中每个像素是4个字节，写一个函数把图像旋转90度。 你能原地进行操作吗？(即不开辟额外的存储空间)
/*********************************
* 日期：2014-05-14
* 作者：SJF0115
* 题目: Rotate Image
* 来源：CareerCup
**********************************/
#include <iostream>
#include <algorithm>
#include <vector>
#include <string.h>
using namespace std;
//旋转图片
void RotateImage(vector<vector<int> > &matrix){
int i,j,temp;
int N = matrix.size();
// 沿着副对角线反转
for(i = 0; i < N;i++){
for(j = 0;j < N - i;j++){
temp = matrix[i][j];
matrix[i][j] = matrix[N - 1 - j][N - 1 - i];
matrix[N - 1 - j][N - 1 - i] = temp;
}
}
// 沿着水平中线反转
for(i = 0; i < N / 2;i++){
for (j = 0; j < N;j++){
temp = matrix[i][j];
matrix[i][j] = matrix[N - 1 - i][j];
matrix[N - 1 - i][j] = temp;
}
}
}
int main(){
vector<int> row1 = {1,2,3};
vector<int> row2 = {4,5,6};
vector<int> row3 = {7,8,9};
vector<vector<int>> matrix;
matrix.push_back(row1);
matrix.push_back(row2);
matrix.push_back(row3);
RotateImage(matrix);
for(int i = 0;i < 3;i++){
for(int j = 0;j < 3;j++){
cout<<matrix[i][j]<<" ";
}
cout<<endl;
}
return 0;
}
CareerCup之1.6 Rotate Image,布布扣,bubuko.com
原文地址：http://blog.csdn.net/sunnyyoona/article/details/25773331
