标签:更新 should design last == fun public inter struct
Design your implementation of the linked list. You can choose to use the singly linked list or the doubly linked list. A node in a singly linked list should have two attributes: val
and next
. val
is the value of the current node, and next
is a pointer/reference to the next node. If you want to use the doubly linked list, you will need one more attribute prev
to indicate the previous node in the linked list. Assume all nodes in the linked list are 0-indexed.
Implement these functions in your linked list class:
index
-th node in the linked list. If the index is invalid, return -1
.val
before the first element of the linked list. After the insertion, the new node will be the first node of the linked list.val
to the last element of the linked list.val
before the index
-th node in the linked list. If index
equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted.index
-th node in the linked list, if the index is valid.Example:
MyLinkedList linkedList = new MyLinkedList(); linkedList.addAtHead(1); linkedList.addAtTail(3); linkedList.addAtIndex(1, 2); // linked list becomes 1->2->3 linkedList.get(1); // returns 2 linkedList.deleteAtIndex(1); // now the linked list is 1->3 linkedList.get(1); // returns 3
Note:
[1, 1000]
.[1, 1000]
.
注意要实时更新head, tail!!
class MyLinkedList { class ListNode { int val; ListNode next; public ListNode(int x) { this.val = x; } } ListNode head; ListNode tail; int size; /** Initialize your data structure here. */ public MyLinkedList() { head = null; tail = null; size = 0; } /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */ public int get(int index) { if(index < 0 || index >= size) { return -1; } ListNode cur = head; while(index > 0) { cur = cur.next; index--; } return cur.val; } /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */ public void addAtHead(int val) { ListNode newHead = new ListNode(val); newHead.next = head; head = newHead; if(tail == null) { tail = head; } size++; } /** Append a node of value val to the last element of the linked list. */ public void addAtTail(int val) { ListNode newTail = new ListNode(val); if(tail == null) { head = new ListNode(val); } else { tail.next = newTail; } tail = newTail; size++; } /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */ public void addAtIndex(int index, int val) { if(index < 0 || index > size) { return; } ListNode node = new ListNode(val); if(index == 0) { addAtHead(val); return; } if(index == size) { addAtTail(val); return; } ListNode cur = head; while(index > 1) { cur = cur.next; index--; } ListNode tmp = cur.next; cur.next = node; node.next = tmp; size++; } /** Delete the index-th node in the linked list, if the index is valid. */ public void deleteAtIndex(int index) { if(size == 0 || index < 0 || index >= size) { return; } if(index == 0) { if(size == 1) { head = null; tail = null; size = 0; return; } head = head.next; size--; return; } else { ListNode cur = head; int cnt = index; while(cnt > 1) { cur = cur.next; cnt--; } if(index == size - 1) { tail = cur; tail.next = null; size--; return; } cur.next = cur.next.next; size--; } } } /** * Your MyLinkedList object will be instantiated and called as such: * MyLinkedList obj = new MyLinkedList(); * int param_1 = obj.get(index); * obj.addAtHead(val); * obj.addAtTail(val); * obj.addAtIndex(index,val); * obj.deleteAtIndex(index); */
707. Design Linked List - Easy
标签:更新 should design last == fun public inter struct
原文地址:https://www.cnblogs.com/fatttcat/p/10182916.html