标签:就是 def 数字 递归 NPU turn put inpu return
二分法
掐头结尾取中间
查找效率非常的高
# 二分法查找主要的作用就是查找元素 # lst = [1,3,5,7,12,36,68,79] # 数据集 百万级数据 # nl = int(input("请输入你要查找的数字:")) # left = 0 # right = len(lst)-1 # while left <= right: # mid = (left+right)//2 # if nl > lst[mid]: # left = mid + 1 # elif nl < lst[mid]: # right = mid - 1 # else: # print("存在") # break # else: # print("不存在") # 递归 # def func(n, lst, left, right): # mid = (left+right) // 2 # if left <= right: # if n > lst[mid]: # left = mid + 1 # return func(n, lst, left, right) # elif n < lst[mid]: # right = mid - 1 # return func(n, lst, left, right) # else: # print("存在") # return mid # else: # print("不存在") # return -1 # n = int(input("请输入你要查找的数:")) # lst = [1,3,5,7,12,36,68,79] # func(n, lst, 0, len(lst)-1)
标签:就是 def 数字 递归 NPU turn put inpu return
原文地址:https://www.cnblogs.com/YangWenYu-6/p/10187562.html