leetcode - Valid Number

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Validate if a given string is numeric.

Some examples:
"0" => true
" 0.1 " => true
"abc" => false
"1 a" => false
"2e10" => true

Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.

//有限状态自动机，DFA.
class Solution
{
public:
    bool isNumber(const char *s)
    {
        enum InputType
        {
            INVALID,    // 0
            SPACE,      // 1
            SIGN,       // 2
            DIGIT,      // 3
            DOT,        // 4
            EXPONENT,   // 5
            NUM_INPUTS  // 6
        };
        int transitionTable[][NUM_INPUTS] =
        {
            -1,  0,  3,  1,  2, -1,     // next states for state 0
            -1,  8, -1,  1,  4,  5,     // next states for state 1
            -1, -1, -1,  4, -1, -1,     // next states for state 2
            -1, -1, -1,  1,  2, -1,     // next states for state 3
            -1,  8, -1,  4, -1,  5,     // next states for state 4
            -1, -1,  6,  7, -1, -1,     // next states for state 5
            -1, -1, -1,  7, -1, -1,     // next states for state 6
            -1,  8, -1,  7, -1, -1,     // next states for state 7
            -1,  8, -1, -1, -1, -1,     // next states for state 8
        };
        
        int state = 0;
        while (*s != '\0')
        {
            InputType inputType = INVALID;
            if (isspace(*s))
                inputType = SPACE;
            else if (*s == '+' || *s == '-')
                inputType = SIGN;
            else if (isdigit(*s))
                inputType = DIGIT;
            else if (*s == '.')
                inputType = DOT;
            else if (*s == 'e' || *s == 'E')
                inputType = EXPONENT;
            
            state = transitionTable[state][inputType];
            
            if (state == -1)
                return false;
            else
                ++s;
        }
        
        return state == 1 || state == 4 || state == 7 || state == 8;
    }
};

leetcode - Valid Number

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原文地址：http://blog.csdn.net/akibatakuya/article/details/40087375