标签:rds 输出 public turn seve leetcode ber tee solution
将非负整数转换为其对应的英文表示。可以保证给定输入小于 231 - 1 。
示例 1:
输入: 123
输出: "One Hundred Twenty Three"
示例 2:
输入: 12345
输出: "Twelve Thousand Three Hundred Forty Five"
示例 3:
输入: 1234567
输出: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
示例 4:
输入: 1234567891
输出: "One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"
1 class Solution { 2 static String num1[]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"}; 3 static String num2[]={"Ten","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"}; 4 static String tens[]={"Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"}; 5 public String numberToWords(int num) { 6 if(num==0){ 7 return "Zero"; 8 } 9 String result=""; 10 if(num>999999999){ 11 result+=numberToWordsWithThreeDIgit(num/1000000000)+" Billion"; 12 num%=1000000000; 13 } 14 if(num>999999){ 15 result+=numberToWordsWithThreeDIgit(num/1000000)+" Million"; 16 num%=1000000; 17 } 18 if(num>999){ 19 result+=numberToWordsWithThreeDIgit(num/1000)+" Thousand"; 20 num%=1000; 21 } 22 if(num>0){ 23 result+=numberToWordsWithThreeDIgit(num); 24 } 25 return result.trim(); 26 } 27 28 public String numberToWordsWithThreeDIgit(int num){ 29 String result=""; 30 if(num>99){ 31 result+=" "+num1[num/100-1]+" Hundred"; 32 } 33 num%=100; 34 if(num>19){ 35 result+=" "+tens[num/10-2]; 36 num%=10; 37 }else if(num>9){ 38 result+=" "+num2[num-10]; 39 num=0; 40 } 41 if(num>0){ 42 result+=" "+num1[num-1]; 43 } 44 return result; 45 } 46 }
标签:rds 输出 public turn seve leetcode ber tee solution
原文地址:https://www.cnblogs.com/kexinxin/p/10204954.html