解题：九省联考2018 IIIDX

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<algorithm>
 4 using namespace std;
 5 const int N=500005,M=2e6+20;
 6 int val[N],fth[N],siz[N],lst[N];
 7 int n,minn[M],laz[M],rnk[N]; 
 8 double k;
 9 bool cmp(int x,int y)
10 {
11     return x>y;
12 }
13 void Release(int nde)
14 {
15     if(laz[nde])
16     {
17         int ls=2*nde,rs=2*nde+1;
18         minn[ls]+=laz[nde],minn[rs]+=laz[nde];
19         laz[ls]+=laz[nde],laz[rs]+=laz[nde],laz[nde]=0;
20     }
21 }
22 void Create(int nde,int l,int r)
23 {
24     if(l==r)
25         minn[nde]=l;
26     else
27     {
28         int mid=(l+r)/2,ls=2*nde,rs=2*nde+1;
29         Create(ls,l,mid),Create(rs,mid+1,r);
30         minn[nde]=min(minn[ls],minn[rs]);
31     }
32 }
33 void Change(int nde,int l,int r,int ll,int rr,int tsk)
34 {
35     if(l>rr||r<ll)
36         return ;
37     else if(l>=ll&&r<=rr)
38         minn[nde]+=tsk,laz[nde]+=tsk;
39     else
40     {
41         int mid=(l+r)/2,ls=2*nde,rs=2*nde+1; Release(nde);
42         Change(ls,l,mid,ll,rr,tsk),Change(rs,mid+1,r,ll,rr,tsk);
43         minn[nde]=min(minn[ls],minn[rs]);
44     }
45 }
46 int Query(int nde,int l,int r,int tsk)
47 {
48     if(l==r)
49         return l+(tsk>minn[nde]);
50     else
51     {
52         int mid=(l+r)/2,ls=2*nde,rs=2*nde+1; Release(nde);
53         return (tsk<=minn[rs])?Query(ls,l,mid,tsk):Query(rs,mid+1,r,tsk);
54     }
55 }
56 int main()
57 {
58     scanf("%d%lf",&n,&k);
59     for(int i=1;i<=n;i++)
60         scanf("%d",&val[i]),siz[i]=1;
61     sort(val+1,val+1+n,cmp);
62     for(int i=n;i;i--)
63     {
64         fth[i]=1.0*i/k,siz[fth[i]]+=siz[i];
65         if(val[i]==val[i+1]) lst[i]=lst[i+1]+1;
66     }
67     Create(1,1,n);
68     for(int i=1;i<=n;i++)
69     {
70         if(fth[i]!=fth[i-1]) 
71             Change(1,1,n,rnk[fth[i]],n,siz[fth[i]]-1);
72         int ans=Query(1,1,n,siz[i]);
73         ans+=lst[ans],lst[ans]++,ans-=lst[ans]-1;
74         rnk[i]=ans,Change(1,1,n,ans,n,-siz[i]);
75     }
76     for(int i=1;i<=n;i++)
77         printf("%d ",val[rnk[i]]);
78     return 0;
79 }