标签:poj1797
Time Limit: 3000MS | Memory Limit: 30000K | |
Total Submissions: 21037 | Accepted: 5569 |
Description
Input
Output
Sample Input
1 3 3 1 2 3 1 3 4 2 3 5
Sample Output
Scenario #1: 4
Source
#include <stdio.h> #include <string.h> #define maxn 1010 #define maxm maxn * maxn #define inf 0x3f3f3f3f int head[maxn], n, m, id, ans, cas = 1; struct Node { int v, c, next; } E[maxm]; bool vis[maxn]; void addEdge(int u, int v, int c) { E[id].v = v; E[id].c = c; E[id].next = head[u]; head[u] = id++; E[id].v = u; E[id].c = c; E[id].next = head[v]; head[v] = id++; } void getMap() { int u, v, c; id = 0; scanf("%d%d", &n, &m); memset(head, -1, sizeof(int) * (n + 1)); while(m--) { scanf("%d%d%d", &u, &v, &c); addEdge(u, v, c); } } void DFS(int k, int dis) { if(k == n) { if(dis > ans) ans = dis; return; } for(int i = head[k]; i != -1; i = E[i].next) { if(!vis[E[i].v]) { int pre = dis; vis[E[i].v] = 1; if(E[i].c < dis) dis = E[i].c; DFS(E[i].v, dis); dis = pre; vis[E[i].v] = 0; } } } void solve() { ans = 0; memset(vis, 0, sizeof(bool) * (n + 1)); vis[1] = 1; DFS(1, inf); printf("Scenario #%d:\n%d\n\n", cas++, ans); } int main() { // freopen("stdin.txt", "r", stdin); int t; scanf("%d", &t); while(t--) { getMap(); solve(); } return 0; }
#include <stdio.h> #include <string.h> #define maxn 1010 #define maxm maxn * maxn #define inf 0x3f3f3f3f int head[maxn], n, m, id, ans, cas = 1; struct Node { int v, c, next; } E[maxm]; int dis[maxn]; bool vis[maxn]; int max(int a, int b) { return a > b ? a : b; } int min(int a, int b) { return a < b ? a : b; } void addEdge(int u, int v, int c) { E[id].v = v; E[id].c = c; E[id].next = head[u]; head[u] = id++; E[id].v = u; E[id].c = c; E[id].next = head[v]; head[v] = id++; } void getMap() { int u, v, c; id = 0; scanf("%d%d", &n, &m); memset(head, -1, sizeof(int) * (n + 1)); while(m--) { scanf("%d%d%d", &u, &v, &c); addEdge(u, v, c); } } int getNext() { int pos = -1, val = 0; for(int i = 1; i <= n; ++i) if(dis[i] > val && !vis[i]) { val = dis[i]; pos = i; } return pos; } void Dijkstra(int start, int end) { memset(dis, 0, sizeof(int) * (n + 1)); dis[start] = inf; int i, u = start, v; while(u != -1) { vis[u] = 1; if(u == end) return; for(i = head[u]; i != -1; i = E[i].next) { if(!vis[v = E[i].v]) dis[v] = max(dis[v], min(E[i].c, dis[u])); } u = getNext(); } } void solve() { memset(vis, 0, sizeof(bool) * (n + 1)); Dijkstra(1, n); printf("Scenario #%d:\n%d\n\n", cas++, dis[n]); } int main() { // freopen("stdin.txt", "r", stdin); int t; scanf("%d", &t); while(t--) { getMap(); solve(); } return 0; }
POJ1797 Heavy Transportation 【Dijkstra】
标签:poj1797
原文地址:http://blog.csdn.net/chang_mu/article/details/40143391