Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public ListNode rotateRight(ListNode head, int n) { if(head==null) return head; ListNode ln = head; ListNode last = null; ListNode res = null; int len = 0; while (ln.next != null) { ln = ln.next; len++; } len++; int k = len-(n%(len)); if(k==0||k==len) return head; ListNode ln2 = head; int seq = 0; while (ln2.next != null) { seq++; if (seq == k){ last = ln2; break; } ln2=ln2.next; } ln.next = head; res=last.next; last.next=null; return res; } }
原文地址:http://blog.csdn.net/guorudi/article/details/40147197