CrackMe005全破详解--上篇

  1 void CCM002Dlg::OnOK() 
  2 {
  3     // TODO: Add extra validation here
  4     
  5     //CDialog::OnOK();
  6 
  7     char szKey[1024]={0};
  8     int n = 0;
  9     GetDlgItemText(IDC_EDIT1,szKey,1024);
 10     if(!strlen(szKey))
 11     {
 12         
 13         MessageBox("请按照【前期步骤】获取正确数值后再生成方案！","友情提示");
 14         return;
 15     }
 16     n = GetDlgItemInt(IDC_EDIT1);
 17     
 18     
 19     switch(n){
 20     case 1  :
 21         n=0x3D;
 22         break; 
 23     case 2  :
 24         n=0x34;
 25         break; 
 26     case 3  :
 27         n=0xDF;
 28         break; 
 29         
 30     default : // 可选的
 31         n=0x41;
 32     }
 33     
 34     
 35     struct  image
 36     {
 37         char szname[7];
 38         int nNumber ;
 39         int nLef;
 40         int nRight;
 41     };
 42     image aImage[4]={0};
 43     
 44     sprintf(aImage[0].szname,"人之初");
 45     aImage[0].nNumber = 1;
 46     aImage[0].nLef = 0x2;
 47     aImage[0].nRight = 0x11;
 48     
 49     sprintf(aImage[1].szname,"性本善");
 50     aImage[1].nNumber = 2;
 51     aImage[1].nLef = 0x3;
 52     aImage[1].nRight = 0x13;
 53     
 54     sprintf(aImage[2].szname,"性相近");
 55     aImage[2].nNumber = 3;
 56     aImage[2].nLef = 0x5;
 57     aImage[2].nRight = 0x17;
 58     
 59     sprintf(aImage[3].szname,"习相远");
 60     aImage[3].nNumber = 4;
 61     aImage[3].nLef = 0x7;
 62     aImage[3].nRight = 0x1B;
 63     /************************************************************************/
 64     /* 设计原则，选择出点击次数最少的方案
 65     /* iR作为大数数组下标,iL作为小数数组下标,j大数商,k小数商,求i+j最小值                                                                
 66     /************************************************************************/
 67     int nRes = 112;
 68     int nIL = 0;
 69     int nIR = 0;
 70     int nJ = 0;
 71     int nK =0 ;
 72     for (int iL=0;iL<4;iL++)
 73     {
 74         for (int iR=0;iR < 4;iR++)
 75         {
 76             
 77             for (int j=1;j<=14;j++)
 78             {
 79                 for (int k =0;k<=112;k++)
 80                 {
 81                     
 82                     if ((aImage[iR].nRight*j + aImage[iL].nLef*k == n) && (nRes> j+k))
 83                     {
 84                         nIL = iL;
 85                         nIR = iR;
 86                         nJ = j;
 87                         nK = k;
 88                         nRes = j+k ;
 89                     }
 90                     
 91                 }
 92             }
 93         }
 94         
 95     }
 96     
 97     sprintf(szKey,"在“%s”图片时左键点击图片%d次\r\n\r\n在“%s”图片时右键点击图片%d次\r\n\r\n即可注册成功!",aImage[nIL].szname,nK,aImage[nIR].szname,nJ);
 98     SetDlgItemText(IDC_EDIT2,szKey);
 99 
100    
101 }