标签：int mem const wap asc graph star ati leetcode
Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.
If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).
The replacement must be in-place and use only constant extra memory.
Here are some examples. Inputs are in the left-hand column and its corresponding outputs are in the right-hand column.
1,2,3 → 1,3,2
3,2,1 → 1,2,3
1,1,5 → 1,5,1
public class Solution { public void nextPermutation(int[] nums) { int i = nums.length - 2; while (i >= 0 && nums[i + 1] <= nums[i]) { i--; } if (i >= 0) { int j = nums.length - 1; while (j >= 0 && nums[j] <= nums[i]) { j--; } swap(nums, i, j); } reverse(nums, i + 1); } private void reverse(int[] nums, int start) { int i = start, j = nums.length - 1; while (i < j) { swap(nums, i, j); i++; j--; } } private void swap(int[] nums, int i, int j) { int temp = nums[i]; nums[i] = nums[j]; nums[j] = temp; } }
[LeetCode]31. Next Permutation下一个排列
标签：int mem const wap asc graph star ati leetcode
原文地址：https://www.cnblogs.com/jchen104/p/10332056.html
