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38. Count and Say

时间:2019-01-30 00:12:51      阅读:143      评论:0      收藏:0      [点我收藏+]

标签:input   toc   while   end   and   string   win   put   count   

The count-and-say sequence is the sequence of integers with the first five terms as following:

1.     1
2.     11
3.     21
4.     1211
5.     111221

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n where 1 ≤ n ≤ 30, generate the nth term of the count-and-say sequence.

Note: Each term of the sequence of integers will be represented as a string.

 

Example 1:

Input: 1
Output: "1"

Example 2:

Input: 4
Output: "1211"
class Solution {
public String countAndSay(int n) {
        StringBuilder sb1 = new StringBuilder("1"), sb2 = sb1;
        while(--n > 0){
            sb2 = new StringBuilder();
            int c = 1, i = 0;
            char[] ch = sb1.toString().toCharArray();
            while(i < sb1.length()){
                if(i+1 < sb1.length() && ch[i] == ch[i+1]) ++c;
                else{
                    sb2.append(c).append(ch[i]);
                    c = 1;
                }
                ++i;
            }
            sb1 = sb2;
        }
        
        return sb2.toString();
    }
}

来自leetcode,高效简洁

38. Count and Say

标签:input   toc   while   end   and   string   win   put   count   

原文地址:https://www.cnblogs.com/wentiliangkaihua/p/10336371.html

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