写一个函数返回参数二进制中1的个数

 1 #include<stdio.h>
 2 
 3 int count_one_bits(unsigned int value)
 4 {
 5     int count = 0;
 6     while (value / 2 != 0)
 7     {
 8         if (value % 2 == 1)
 9         {
10             ++count;
11             value = value / 2;
12             if (value == 1)
13             {
14                 ++count;
15                 continue;
16             }
17         }
18         else
19         {
20             value = value / 2;
21             if (value == 1)
22             {
23                 ++count;
24                 continue;
25             }
26         }
27     }
28     return count;
29 }
30 
31 int main()
32 {
33     int i;
34     printf("请输入数字：\n");
35     scanf("%d", &i);
36     int num = count_one_bits(i);
37     printf("%d", num);
38     return 0;
39 }

 1 #define _CRT_SECURE_NO_WARNINGS
 2 #include<stdio.h>
 3 
 4 int Count_one_bits(int a)
 5 {
 6     int count = 0;
 7     while (a!=0)
 8     {
 9         if (a & 1 == 1)
10         {
11             ++count;
12             a = a >> 1;
13         }
14         else
15         {
16             a = a >> 1;
17         }
18     }
19     return count;
20 }
21 
22 int main()
23 {
24     //int c;
25     //int b = 6; //0000 0110
26     //int a = 11;//0000 1011
27     //           //printf("%d\n",a >> 1);//0000 0101 (5)
28     //           //printf("%d\n",a << 1);//0001 0110 (22)
29     //c = a & b;//2   0000 0010
30     //printf("%d", c);
31     int a;
32     printf("请输入数字：\n");
33     scanf("%d",&a);
34     int count = Count_one_bits(a);
35     printf("%d",count);
36 
37     return 0;
38 }