标签：ucs file uniq 超时 scripts size contains abs lock
https://pintia.cn/problem-sets/994805342720868352/problems/994805480801550336
A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID‘s.
Each input file contains one test case. For each case, the first line contains a positive integer N (≤10?4??) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:
It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.
After the book information, there is a line containing a positive integer M (≤1000) which is the number of user‘s search queries. Then M lines follow, each in one of the formats shown below:
For each query, first print the original query in a line, then output the resulting book ID‘s in increasing order, each occupying a line. If no book is found, print Not Found instead.
3
1111111
The Testing Book
Yue Chen
test code debug sort keywords
ZUCS Print
2011
3333333
Another Testing Book
Yue Chen
test code sort keywords
ZUCS Print2
2012
2222222
The Testing Book
CYLL
keywords debug book
ZUCS Print2
2011
6
1: The Testing Book
2: Yue Chen
3: keywords
4: ZUCS Print
5: 2011
3: blablabla
1: The Testing Book
1111111
2222222
2: Yue Chen
1111111
3333333
3: keywords
1111111
2222222
3333333
4: ZUCS Print
1111111
5: 2011
1111111
2222222
3: blablabla
Not Found
代码：
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e4 + 10;
int N, M;
struct Node {
int title;
string kind; // 1
string author; // 2
string keyword; // 3
string name; // 4
int year; // 5
bool flag = false;
}node[maxn];
int main() {
scanf("%d", &N);
for(int i = 0; i < N; i ++) {
string s1, s2, s3, s4;
int t, n;
scanf("%d", &t); node[i].title = t;
cin.ignore();
getline(cin, s1); node[i].kind = s1;
getline(cin, s2); node[i].author = s2;
getline(cin, s3); node[i].keyword = s3;
getline(cin, s4); node[i].name = s4;
scanf("%d", &n); node[i].year = n;
}
scanf("%d", &M);
cin.ignore();
while(M --) {
vector<int> ans;
ans.clear();
string s;
string rec = "";
getline(cin, s);
cout << s << endl;
int len = s.length();
for(int i = 3; i < len; i ++)
rec += s[i];
if(s[0] == ‘1‘) {
for(int i = 0; i <= N; i ++) {
if(node[i].kind == rec)
ans.push_back(node[i].title);
}
} else if(s[0] == ‘2‘) {
for(int i = 0; i < N; i ++) {
if(node[i].author == rec)
ans.push_back(node[i].title);
}
} else if(s[0] == ‘3‘) {
for(int i = 0; i < N; i ++) {
for(int j = 0; j < node[i].keyword.length(); j ++) {
if(node[i].keyword[j] != ‘ ‘ && (j == 0 || node[i].keyword[j - 1] == ‘ ‘)) {
if(node[i].keyword.substr(j, rec.length()) == rec)
{node[i].flag = true; continue;}
}
}
if(node[i].flag) {
ans.push_back(node[i].title);
node[i].flag = false;
}
}
} else if(s[0] == ‘4‘) {
for(int i = 0; i < N; i ++) {
if(node[i].name == rec)
ans.push_back(node[i].title);
}
} else {
int res = 0;
for(int i = 0; i <= 3; i ++)
res = res * 10 + (rec[i] - ‘0‘);
for(int i = 0; i < N; i ++) {
if(node[i].year == res)
ans.push_back(node[i].title);
}
}
if(ans.size()) {
sort(ans.begin(), ans.end());
for(int i = 0; i < ans.size(); i ++)
printf("%07d\n", ans[i]);
} else printf("Not Found\n");
}
return 0;
}
在 op == 3 的时候优化一下就不会超时了
FH
标签：ucs file uniq 超时 scripts size contains abs lock
原文地址：https://www.cnblogs.com/zlrrrr/p/10366941.html
