标签:code solution div ott 暴力 == size tco 范围
1 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 2 class Solution 3 { 4 public: 5 int orangesRotting(vector<vector<int>>& grid) 6 { 7 int left = 0; 8 int sz1 = grid.size(); 9 int sz2 = grid[0].size(); 10 _for(i,0,sz1) 11 _for(j,0,sz2) 12 if(grid[i][j]==1) 13 left ++; 14 15 int prev = left; 16 int rnt = 0; 17 while(left) 18 { 19 prev = left; 20 _for(i,0,sz1) 21 _for(j,0,sz2) 22 { 23 if(grid[i][j]==2) 24 { 25 if(i+1<sz1&&grid[i+1][j]==1) 26 { 27 left--; 28 grid[i+1][j]=-1; 29 } 30 if(i-1>=0&&grid[i-1][j]==1) 31 { 32 left--; 33 grid[i-1][j]=-1; 34 } 35 if(j-1>=0&&grid[i][j-1]==1) 36 { 37 left--; 38 grid[i][j-1]=-1; 39 } 40 if(j+1<sz2&&grid[i][j+1]==1) 41 { 42 left--; 43 grid[i][j+1]=-1; 44 } 45 } 46 } 47 48 _for(i,0,sz1) 49 _for(j,0,sz2) 50 if(grid[i][j]==-1) 51 grid[i][j] = 2; 52 rnt ++; 53 if(prev==left) 54 return -1; 55 } 56 return rnt; 57 } 58 };
原则上来说,应该用BFS,看了一下数据范围,决定无脑暴力撸过
Leetcode-994 Rotting Oranges(腐烂的橘子)
标签:code solution div ott 暴力 == size tco 范围
原文地址:https://www.cnblogs.com/Asurudo/p/10390642.html