Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
public class Solution { private int f[][]; private int g[][]; public int minPathSum(int[][] grid) { int m = grid.length; int n = grid[0].length; f = new int[m+1][n+1]; g= grid; return dfs(m,n); } private int dfs(int m,int n){ if(m<1||n<1) return 2000000000; if(m==1&&n==1) return g[0][0]; return Math.min(help(m-1,n),help(m,n-1))+g[m-1][n-1]; } private int help(int m,int n){ if(f[m][n]>0) return f[m][n]; return f[m][n] = dfs(m,n); } }
原文地址:http://blog.csdn.net/guorudi/article/details/40191473