标签：删除 return active anim img lower header can code
Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome.
Example 1:
Input: "aba" Output: True
Example 2:
Input: "abca" Output: True Explanation: You could delete the character ‘c‘.
Note:
class Solution { public boolean validPalindrome(String s) { int i = -1, j = s.length(); while(++i < --j) { if(s.charAt(i) != s.charAt(j)) return isPalindrome(s,i+1,j) || isPalindrome(s,i,j-1); } return true; } private boolean isPalindrome(String s, int i, int j) { while(i < j) { if(s.charAt(i++) != s.charAt(j--)) return false; } return true; } }
680. Valid Palindrome II【Easy】【双指针-可以删除一个字符，判断是否能构成回文字符串】
标签：删除 return active anim img lower header can code
原文地址：https://www.cnblogs.com/Roni-i/p/10427154.html
