标签：one char return flag NPU color tle online false
Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fufirst if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: zero (ling) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai.
Each input file contains one test case, which gives an integer with no more than 9 digits.
For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.
-123456789
Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu
100800
yi Shi Wan ling ba Bai
分析： 这个题有点复杂。。慢慢模拟。。debug了好久，要注意一个数中间空了多个零，只要输出一个零。。。
一开始没注意，女朋友随便给我出了个数。。竟然真错在这里了，她是不是有干测试的潜质= =
1 /**
2 * Copyright(c)
3 * All rights reserved.
4 * Author : Mered1th
5 * Date : 2019-02-24-22.11.37
6 * Description : A1082
7 */
8 #include<cstdio>
9 #include<cstring>
10 #include<iostream>
11 #include<cmath>
12 #include<algorithm>
13 #include<string>
14 #include<unordered_set>
15 #include<map>
16 #include<vector>
17 #include<set>
18 using namespace std;
19 string num[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
20 string c[2]={"Yi","Wan"};
21
22 void func(int n){
23 string s=to_string(n);
24 if(s.size()==1){
25 cout<<num[s[0]-‘0‘];
26 }
27 else if(s.size()==2){
28 cout<<num[s[0]-‘0‘]<<" "<<"Shi";
29 if(s[1]!=‘0‘){
30 cout<<" "<<num[s[1]-‘0‘];
31 }
32 }
33 else if(s.size()==3){
34 cout<<num[s[0]-‘0‘]<<" "<<"Bai";
35 if(s[1]==‘0‘){
36 if(s[2]!=‘0‘){
37 cout<<" ling "<<num[s[2]-‘0‘];
38 }
39 }
40 else{
41 cout<<" "<<num[s[1]-‘0‘]<<" Shi";
42 if(s[2]!=‘0‘){
43 cout<<" "<<num[s[2]-‘0‘];
44 }
45 }
46 }
47 else if(s.size()==4){
48 cout<<num[s[0]-‘0‘]<<" Qian";
49 if(s[1]==‘0‘){
50 if(s[2]==‘0‘){
51 if(s[3]!=‘0‘){
52 cout<<" ling "<<num[s[3]-‘0‘];
53 }
54 }
55 else{
56 cout<<" ling "<<num[s[2]-‘0‘]<<" Shi";
57 if(s[3]!=‘0‘){
58 cout<<" "<<num[s[3]-‘0‘];
59 }
60 }
61 }
62 else{
63 cout<<" "<<num[s[1]-‘0‘]<<" Bai";
64 if(s[2]==‘0‘){
65 if(s[3]!=‘0‘){
66 cout<<" ling "<<num[s[3]-‘0‘];
67 }
68 }
69 else{
70 cout<<" "<<num[s[2]-‘0‘]<<" Shi";
71 if(s[3]!=‘0‘){
72 cout<<" "<<num[s[3]-‘0‘];
73 }
74 }
75 }
76 }
77 }
78
79 int main(){
80 #ifdef ONLINE_JUDGE
81 #else
82 freopen("1.txt", "r", stdin);
83 #endif
84 int s;
85 cin>>s;
86 if(s==0){
87 printf("ling");
88 return 0;
89 }
90 if(s<0){
91 printf("Fu ");
92 s=-s;
93 }
94 int s1=s/100000000;
95 int s2=s%100000000/10000;
96 int s3=s%10000;
97 bool flag=false;
98 if(s1){
99 func(s1);
100 cout<<" "<<c[0]<<" ";
101 }
102 if(s2){
103 string t2=to_string(s2);
104 if(s1 && t2.size()<4){
105 for(int i=1;i<=t2.size();i++){
106 if(t2[i]!=‘0‘){
107 cout<<"ling ";
108 }
109 }
110 }
111 func(s2);
112 cout<<" "<<c[1]<<" ";
113 }
114 if(s3){
115 if(s1!=0 && s2==0){
116 cout<<"ling ";
117 flag=true;
118 }
119 string t3=to_string(s3);
120 if( ( s1 || s2) && t3.size()<4){
121 for(int i=1;i<=t3.size();i++){
122 if(t3[i]!=‘0‘ && flag==false){
123 cout<<"ling ";
124 flag=true;
125 }
126 }
127 }
128 func(s3);
129 }
130 return 0;
131 }
1082 Read Number in Chinese （25 分）
标签：one char return flag NPU color tle online false
原文地址：https://www.cnblogs.com/Mered1th/p/10428750.html
