标签：ext name mes pen .com \n input 题目 get
http://codeforces.com/contest/63
1 #include<bits/stdc++.h> 2 using namespace std; 3 #define lson l,mid,rt<<1 4 #define rson mid+1,r,rt<<1|1 5 #define sqr(x) ((x)*(x)) 6 #define pb push_back 7 #define eb emplace_back 8 #define maxn 1000006 9 #define rep(k,i,j) for(int k=i;k<j;k++) 10 typedef long long ll; 11 typedef unsigned long long ull; 12 13 struct sair{ 14 string name,v; 15 }a[105]; 16 17 int main(){ 18 #ifndef ONLINE_JUDGE 19 freopen("input.txt","r",stdin); 20 #endif 21 std::ios::sync_with_stdio(false); 22 int n; 23 cin>>n; 24 rep(i,1,n+1){ 25 cin>>a[i].name>>a[i].v; 26 } 27 rep(i,1,n+1){ 28 if(a[i].v=="rat"){ 29 cout<<a[i].name<<endl; 30 } 31 } 32 rep(i,1,n+1){ 33 if(a[i].v=="woman"||a[i].v=="child"){ 34 cout<<a[i].name<<endl; 35 } 36 } 37 rep(i,1,n+1){ 38 if(a[i].v=="man"){ 39 cout<<a[i].name<<endl; 40 } 41 } 42 rep(i,1,n+1){ 43 if(a[i].v=="captain"){ 44 cout<<a[i].name<<endl; 45 } 46 } 47 }
暴力模拟即可
1 #include<bits/stdc++.h> 2 using namespace std; 3 #define lson l,mid,rt<<1 4 #define rson mid+1,r,rt<<1|1 5 #define sqr(x) ((x)*(x)) 6 #define pb push_back 7 #define eb emplace_back 8 #define maxn 1000006 9 #define rep(k,i,j) for(int k=i;k<j;k++) 10 typedef long long ll; 11 typedef unsigned long long ull; 12 13 14 int n,k; 15 int a[105]; 16 int book[105]; 17 18 int main(){ 19 #ifndef ONLINE_JUDGE 20 // freopen("input.txt","r",stdin); 21 #endif 22 std::ios::sync_with_stdio(false); 23 cin>>n>>k; 24 int ans=0; 25 rep(i,1,n+1){ 26 cin>>a[i]; 27 } 28 a[0]=-0x3f3f3f3f; 29 sort(a,a+n+1); 30 int flag=1; 31 while(flag){ 32 flag=0; 33 rep(i,1,n+1){ 34 if(a[i]<k) 35 if(a[i]!=a[i-1]){ 36 book[i]++; 37 flag=1; 38 } 39 } 40 rep(i,0,n+1) a[i]+=book[i],book[i]=0; 41 sort(a,a+n+1); 42 ans+=flag; 43 } 44 cout<<ans<<endl; 45 }
枚举1-9999的数，然后一个个判断，看看有几个符合条件
1 #include<bits/stdc++.h> 2 using namespace std; 3 #define lson l,mid,rt<<1 4 #define rson mid+1,r,rt<<1|1 5 #define sqr(x) ((x)*(x)) 6 #define pb push_back 7 #define eb emplace_back 8 #define maxn 1000006 9 #define rep(k,i,j) for(int k=i;k<j;k++) 10 typedef long long ll; 11 typedef unsigned long long ull; 12 13 14 int n; 15 struct sair{ 16 int a,b,c; 17 }q[15]; 18 19 int main(){ 20 #ifndef ONLINE_JUDGE 21 // freopen("input.txt","r",stdin); 22 #endif 23 // std::ios::sync_with_stdio(false); 24 cin>>n; 25 rep(i,0,n) { 26 cin>>q[i].a>>q[i].b>>q[i].c; 27 } 28 int x,y,z; 29 int ans,num=0; 30 rep(i,0,10000){ 31 int tmp=i; 32 int a,b,c,d; 33 a=tmp%10,tmp/=10; 34 b=tmp%10,tmp/=10; 35 c=tmp%10,tmp/=10; 36 d=tmp%10; 37 if(a==b||a==c||a==d||b==c||b==d||c==d) continue; 38 int flag=1; 39 rep(j,0,n){ 40 x=0,y=0,z; 41 tmp=q[j].a; 42 z=tmp%10; 43 if(a==z) x++; 44 if(b==z) y++; 45 if(c==z) y++; 46 if(d==z) y++; 47 tmp/=10; 48 z=tmp%10; 49 if(b==z) x++; 50 if(a==z) y++; 51 if(c==z) y++; 52 if(d==z) y++; 53 tmp/=10; 54 z=tmp%10; 55 if(c==z) x++; 56 if(b==z) y++; 57 if(a==z) y++; 58 if(d==z) y++; 59 tmp/=10; 60 z=tmp%10; 61 if(d==z) x++; 62 if(b==z) y++; 63 if(c==z) y++; 64 if(a==z) y++; 65 if(x!=q[j].b||y!=q[j].c){ 66 flag=0; 67 break; 68 } 69 } 70 if(flag){ 71 num++; 72 ans=i; 73 } 74 } 75 if(num==0) cout<<"Incorrect data"<<endl; 76 else if(num==1) printf("%04d\n",ans); 77 else cout<<"Need more data"<<endl; 78 }
通过多次模拟可以发现，只要走S形即可
1 #include<bits/stdc++.h> 2 using namespace std; 3 #define lson l,mid,rt<<1 4 #define rson mid+1,r,rt<<1|1 5 #define sqr(x) ((x)*(x)) 6 #define pb push_back 7 #define eb emplace_back 8 #define maxn 1000006 9 #define rep(k,i,j) for(int k=i;k<j;k++) 10 typedef long long ll; 11 typedef unsigned long long ull; 12 13 int field[55][105]; 14 15 int main(){ 16 #ifndef ONLINE_JUDGE 17 // freopen("input.txt","r",stdin); 18 #endif 19 std::ios::sync_with_stdio(false); 20 int a,b,c,d,n; 21 cin >> a >> b >> c >> d >> n; 22 for (int i=0; i<50; i++) { 23 for (int j=0; j<100; j++) { 24 field[i][j]=0; 25 } 26 } 27 int party[26]={0}; 28 for (int i=0; i<n; i++) { 29 cin >> party[i]; 30 } 31 for (int i=0; i<max(b,d); i++) { 32 for (int j=0; j<a+c; j++) { 33 if ((j<a&&i>=b)||(j>=a&&i>=d))field[i][j]=‘.‘; 34 } 35 } 36 int x=0,y=0,dx=1; 37 if (((b>d)&&(d%2==1))||((d>b)&&(b%2==0))){ 38 x=a+c-1;dx=-1; 39 } 40 for (int i=0; i<n; i++) { 41 for (int j=0; j<party[i]; j++) { 42 field[y][x]=‘a‘+i; 43 if (x+dx<0||x+dx>=a+c||field[y][x+dx]==‘.‘) { 44 dx*=-1; 45 y++; 46 } else { 47 x+=dx; 48 } 49 } 50 } 51 cout << "YES" << endl; 52 for (int i=0; i<max(b,d); i++) { 53 for (int j=0; j<a+c; j++) { 54 cout << char(field[i][j]); 55 } 56 cout << endl; 57 } 58 59 }
一种类似博弈的题目，用状压表示每一种情况，然后搜索，找出Karlsson的必胜路径，找不到的话就是必败
1 #include<bits/stdc++.h> 2 using namespace std; 3 #define lson l,mid,rt<<1 4 #define rson mid+1,r,rt<<1|1 5 #define sqr(x) ((x)*(x)) 6 #define pb push_back 7 #define eb emplace_back 8 #define maxn 1000006 9 #define rep(k,i,j) for(int k=i;k<j;k++) 10 typedef long long ll; 11 typedef unsigned long long ull; 12 13 const int N=19,S=1<<19; 14 15 int Next[3][N]={{3,4,5,7,8,9,10,N,12,13,14,15,N,16,17,18,N,N,N}, 16 {1,2,N,4,5,6,N,8,9,10,11,N,13,14,15,N,17,18,N}, 17 {4,5,6,8,9,10,11,12,13,14,15,N,16,17,18,N,N,N,N}}; 18 19 int dp[S],status=0; 20 21 int dfs(int now){ 22 if(dp[now]) return dp[now]; 23 rep(t,0,3){ 24 rep(i,0,N){ 25 int tmp=now,p=i; 26 while(tmp&(1<<p)){ 27 tmp^=(1<<p); 28 if(dfs(tmp)==2){ 29 return dp[now]=1; 30 } 31 p=Next[t][p]; 32 } 33 } 34 } 35 return dp[now]=2; 36 } 37 38 int main(){ 39 #ifndef ONLINE_JUDGE 40 freopen("input.txt","r",stdin); 41 #endif 42 std::ios::sync_with_stdio(false); 43 char ch; 44 rep(i,0,N){ 45 cin>>ch; 46 if(ch==‘.‘||ch==‘O‘){ 47 if(ch==‘O‘){ 48 status+=(1<<i); 49 } 50 } 51 else{ 52 i--; 53 } 54 } 55 int flag=dfs(status); 56 if(flag==1) cout<<"Karlsson"<<endl; 57 else cout<<"Lillebror"<<endl; 58 }
Codeforces Beta Round #59 (Div. 2)
标签：ext name mes pen .com \n input 题目 get
原文地址：https://www.cnblogs.com/Fighting-sh/p/10453040.html
