【Codeforces 1036C】Classy Numbers

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【链接】 我是链接,点我呀:)
【题意】

让你求出只由3个非0数字组成的数字在[li,ri]这个区间里面有多少个.

【题解】

只由3个非0数字组成的数字在1~10^18中只有60W个
dfs处理出来之后排序做个二分查找一下区间里有多少个就好。

【代码】

import java.io.*;
import java.util.*;

public class Main {
    
    
    static InputReader in;
    static PrintWriter out;
        
    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }
    
    static int N = 700000;
    static class Task{
        TreeSet<Long> myset = new TreeSet<Long>();
        long a[] = new long[N+10];
        int T,n;
        long l,r;
        
        void dfs(long cur,int num,int dep) {
            if (dep==18) {
                if (cur>0) myset.add(cur);  
                return;
            }
            if (num<3) {
                for (int j = 1;j <= 9;j++)
                    dfs(cur*10+j,num+1,dep+1);
            }
            dfs(cur*10,num,dep+1);
        }
        
        int get_least_gore(long x) {
            int l = 1,r = n,temp = 1;
            while (l<=r) {
                int mid = (l+r)/2;
                if (a[mid]>=x) {
                    temp = mid;
                    r = mid - 1;
                }else l = mid + 1;
            }
            return temp;
        }
        
        int get_last_lore(long x) {
            int l = 1,r = n,temp = 1;
            while (l<=r) {
                int mid = (l+r)/2;
                if (a[mid]<=x) {
                    temp = mid;
                    l = mid + 1;
                }else r = mid - 1;
            }
            return temp;
        }
        
        public void solve(InputReader in,PrintWriter out) {
            myset.add((long)1e18);
            dfs(0,0,0);
            n = myset.size();
            Iterator<Long> it = myset.iterator();
            int j = 1;
            while (it.hasNext()) {
                a[j] = it.next();
                j++;
            }
            T = in.nextInt();
            for (int ii = 1;ii <= T;ii++) {
                l = in.nextLong();r = in.nextLong();
                int idx1 = get_least_gore(l);
                int idx2 = get_last_lore(r);
                out.println(idx2-idx1+1);
            }
        }
    }

    

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;
        
        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }
        
        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
        
        public long nextLong() {
            return Long.parseLong(next());
        }
    }
}

【Codeforces 1036C】Classy Numbers

标签：start   二分查找   ati   imp   parse   exti   ber   pre   题意   

原文地址：https://www.cnblogs.com/AWCXV/p/10518123.html