标签:style blog http color io os ar java for
解题思路:用程序实现一个乘法功能,将给定的字符串依次做旋转,然后进行比较。由于题目比较简单,所以不做过多的详解。
具体算法(java版,可以直接AC)
1 import java.util.Scanner; 2 3 public class Main { 4 5 public static void main(String[] args) { 6 Scanner scanner = new Scanner(System.in); 7 String line; 8 while (scanner.hasNext()) { 9 line = scanner.next(); 10 MyNumber number = new MyNumber(line); 11 int count = 0; 12 for (int i = 2; i <= line.length(); i++) { 13 NumNode[] result = number.multiply(i); 14 if (number.isCycle(result)) { 15 count++; 16 } 17 } 18 if (count == line.length()-1) { 19 System.out.println(line + " is cyclic"); 20 } else { 21 System.out.println(line + " is not cyclic"); 22 } 23 } 24 } 25 26 } 27 28 class NumNode { 29 int value; 30 int carry; 31 32 public NumNode() { 33 this.value = 0; 34 this.carry = 0; 35 } 40 } 41 42 class MyNumber { 43 private NumNode[] data; 44 private int length; 45 private String[] rotation; 46 private boolean isRotated; 47 48 public MyNumber(String line) { 49 this.length = line.length(); 50 this.isRotated=false; 51 this.data = new NumNode[this.length]; 52 this.rotation = new String[this.length]; 53 for (int i = this.length - 1; i >= 0; i--) { 54 this.data[i] = new NumNode(); 55 this.data[i].value = line.charAt(i) - ‘0‘; 56 } 57 } 58 59 private void rotate() { 60 for (int i = 0; i < this.length; i++) { 61 StringBuffer buffer = new StringBuffer(); 62 for (int j = i; j < this.length; j++) { 63 buffer.append(this.data[j].value); 64 } 65 for (int j = 0; j < i; j++) { 66 buffer.append(this.data[j].value); 67 } 68 this.rotation[i] = buffer.toString(); 69 } 70 } 71 72 public NumNode[] multiply(int a) { 73 NumNode[] result = new NumNode[this.length]; 74 for (int i = this.length - 1; i >= 0; i--) { 75 int value = this.data[i].value * a; 76 result[i] = new NumNode(); 77 if (i + 1 < this.length) { 78 value += result[i + 1].carry; 79 } 80 result[i].value = value % 10; 81 result[i].carry = value / 10; 82 } 83 return result; 84 } 85 86 public boolean equals(String s) { 87 for (String str : this.rotation) { 88 if (str.equals(s)) 89 return true; 90 } 91 return false; 92 } 93 94 public boolean isCycle(NumNode[] num) { 95 if (num[0].carry > 0) 96 return false; 97 if(!this.isRotated){ 98 this.rotate(); 99 this.isRotated=true; 100 } 101 StringBuffer buffer = new StringBuffer(); 102 for (int i = 0; i < num.length; i++) { 103 buffer.append(num[i].value); 104 } 105 return this.equals(buffer.toString()); 106 } 107 108 public String toString() { 109 StringBuffer buffer = new StringBuffer(); 110 for (int i = 0; i < this.length; i++) { 111 buffer.append(this.data[i].value); 112 } 113 return buffer.toString(); 114 } 115 }
POJ 1047 Round and Round We Go 最详细的解题报告
标签:style blog http color io os ar java for
原文地址:http://www.cnblogs.com/pinxiong/p/4034284.html