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动态规划_leetcode70

时间:2019-03-17 13:53:35      阅读:139      评论:0      收藏:0      [点我收藏+]

标签:leetcode   style   range   cal   else   weight   alc   pre   cli   

class Solution(object):


def climbStairs(self, n):
"""
:type n: int
:rtype: int
"""

self.memo = [-1 for i in range(n+1)]

return self.calcWays1(n)

def calcWays1(self,n):
if n == 1:
return 1
if n == 2:
return 2

else:
return self.climbStairs(n-1) + self.climbStairs(n-2)

def calcWays2(self, n):
if n == 0 or n == 1:
return 1
if self.memo[n] == -1:
self.memo[n] = self.calcWays2(n-1) + self.calcWays2(n-2)


def calcWays3(self, n):
memo = [-1 for i in range(n+1)]

memo[1] = 1
memo[2] = 2


for i in range(3,n+1):
memo[i] = memo[i-1] + memo[i-2]


return memo[n]

动态规划_leetcode70

标签:leetcode   style   range   cal   else   weight   alc   pre   cli   

原文地址:https://www.cnblogs.com/lux-ace/p/10546417.html

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