复杂链表的复制

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        #如果链表为空链表，则返回本身即可
        #如果非空 需要进行复制操作，如果没有特殊指针，
        #只需要复制next都能很快做出来，但是加上特殊指针这就需要一定技巧，
        #因为特殊指针随便指，而你每次找特殊指针所指的节点都需要从头开始遍历找起，
        if not pHead:
            return pHead
        cloNode = pHead
        while cloNode:
            node = RandomListNode(cloNode.label)
            node.next = cloNode.next
            cloNode.next = node
            cloNode = node.next
        cloNode = pHead
        while cloNode:
            node = cloNode.next
            if cloNode.random:
                node.random = cloNode.random.next
            cloNode = node.next
        cloNode = pHead
        pHead = pHead.next
        while cloNode.next:
            node = cloNode.next
            cloNode.next = node.next
            cloNode = node
        return pHead