标签:style blog http color io ar for sp 2014
一开始一直WA,之后发现这道题不止一组输入,改成多组输入之后就过了。
利用map把每个字符串映射到它对应的结点上就行了。
11909467 | 2014-10-19 11:54:00 | Accepted | 3065 | 234MS | 16912K | 2754 B | G++ | KinderRiven |
#include<queue> #include<map> #include<cstdio> #include<string> #include<vector> #include<cstring> #include<algorithm> using namespace std; const int maxn = 55555; const int max_size = 130; char ss[1111][55]; map<string,int>vis; struct Trie{ int next[maxn][max_size]; int fail[maxn]; int val[maxn]; int sz; int root; int num[maxn]; int index(char e){ return e - 31; } void init(){ sz = 0; root = newnode(); } int newnode(){ val[sz] = 0; num[sz] = 0; memset(next[sz],-1,sizeof(next[sz])); sz ++; return sz - 1; } void insert(char *str){ int L = strlen(str); int u = root; for(int i = 0; i < L; i++){ int e = index(str[i]); if(next[u][e] == -1) next[u][e] = newnode(); u = next[u][e]; } val[u] = 1; //有单词 vis[string(str)] = u; } void build(){ //建立失配边 fail[root] = root; queue<int>q; for(int i = 0; i < max_size; i++){ if(next[root][i] == -1) next[root][i] = root; else{ fail[next[root][i]] = root; q.push(next[root][i]); } } while(!q.empty()){ int now = q.front(); q.pop(); for(int i = 0; i < max_size; i++){ if(next[now][i] == -1) next[now][i] = next[fail[now]][i]; else{ //这个点是一个单词的结尾 fail[next[now][i]] = next[fail[now]][i]; q.push(next[now][i]); } } } } void count(char *str){ int now = root; int L = strlen(str); for(int i = 0; i < L; i++){ int e = index(str[i]); now = next[now][e]; int temp = now; while(temp != root){ if(val[temp]){ //如果这个结点是个单词末尾 num[temp] ++; //printf("%d\n",temp); } temp = fail[temp]; } } } }; Trie ac; char _str[2222222]; int main(){ int n; while(scanf("%d",&n) != EOF){ ac.init(); vis.clear(); getchar(); for(int i = 0; i < n ; i ++){ gets(ss[i]); ac.insert(ss[i]); } ac.build(); gets(_str); ac.count(_str); for(int i = 0; i < n; i++){ int t = vis[string(ss[i])]; if(ac.num[t]){ printf("%s: %d\n",ss[i],ac.num[t]); } } } return 0; }
标签:style blog http color io ar for sp 2014
原文地址:http://blog.csdn.net/u013451221/article/details/40261427