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Leetcode | Find Minimum in Rotated Sorted Array

时间:2014-10-19 16:56:55      阅读:192      评论:0      收藏:0      [点我收藏+]

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Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

二分查找就行了。

 1 class Solution {
 2 public:
 3     int findMin(vector<int> &arr) {
 4         if (arr.empty()) return -1;
 5         int l = 0, h = arr.size() - 1, m, min = INT_MAX;
 6         while (l <= h) {
 7             m = l + (h - l) / 2;
 8             if (arr[m] >= arr[l]) {
 9                 if (min > arr[l]) min = arr[l];
10                 l = m + 1;
11             } else {
12                 if (arr[m] < min) min = arr[m];
13                 h = m - 1;
14             }
15         }
16         return min;
17     }
18 };

即使是有重复元素也是一样。

Leetcode | Find Minimum in Rotated Sorted Array

标签:style   blog   color   io   os   ar   for   sp   div   

原文地址:http://www.cnblogs.com/linyx/p/4035033.html

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