标签:blog io os ar for sp 2014 log amp
题目:统计一个矩阵中所有的连通块的个数,按递减输出。
分析:搜索,floodfill。直接利用dfs求解即可。
说明:数组开小了╮(╯▽╰)╭。
#include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> using namespace std; char maps[55][55]; typedef struct tnode { char ch; int count; }type; type data[2000]; int dfs(int x, int y, int n, int m, char c) { if (x < 0 || x >= n || y < 0 || y >= m) return 0; if (maps[x][y] != c) return 0; maps[x][y] = '.'; int sum = 1; sum += dfs(x+1, y, n, m, c); sum += dfs(x-1, y, n, m, c); sum += dfs(x, y+1, n, m, c); sum += dfs(x, y-1, n, m, c); return sum; } int cmp(type a, type b) { if (a.count != b.count) return a.count > b.count; return a.ch < b.ch; } int main() { int n,m,temp,cas = 1; while (~scanf("%d%d",&n,&m) && m) { for (int i = 0 ; i < n ; ++ i) scanf("%s",maps[i]); int count = 0; for (int i = 0 ; i < n ; ++ i) for (int j = 0 ; j < m ; ++ j) if (maps[i][j] != '.') { data[count].ch = maps[i][j]; data[count].count = dfs(i, j, n, m, maps[i][j]); count ++; } sort(data, data+count, cmp); printf("Problem %d:\n",cas ++); for (int i = 0 ; i < count ; ++ i) printf("%c %d\n",data[i].ch,data[i].count); } return 0; }
UVa 10946 - You want what filled?
标签:blog io os ar for sp 2014 log amp
原文地址:http://blog.csdn.net/mobius_strip/article/details/40265081