标签:div code may bsp NPU for one shm script
/** * 1. Two Sum * https://leetcode.com/problems/two-sum/description/ * Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1]. * */ class solustion { fun twoSum(nums: IntArray, target: Int): IntArray { val size = nums.size val map = HashMap<Int, Int>() val result = IntArray(2) for (i in 0..(size - 1)) { val needCheck = target - nums[i] if (map.containsKey(needCheck)) { result.set(0,map.get(needCheck)!!) result.set(1,i) return result } map.put(nums[i], i) } return result } }
标签:div code may bsp NPU for one shm script
原文地址:https://www.cnblogs.com/johnnyzhao/p/10603432.html