标签:hat style tin mod mil exp sed sans div
Given a binary matrix A
, we want to flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed. For example, flipping [1, 1, 0]
horizontally results in [0, 1, 1]
.
To invert an image means that each 0
is replaced by 1
, and each 1
is replaced by 0
. For example, inverting [0, 1, 1]
results in [1, 0, 0]
.
Input: [[1,1,0],[1,0,1],[0,0,0]] Output: [[1,0,0],[0,1,0],[1,1,1]] Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]]. Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]] Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]] Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]. Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
1 <= A.length = A[0].length <= 20
0 <= A[i][j] <= 1
Title is clear.
[[1,1,0],[1,0,1],[0,0,0]]
class Solution(object):
def flipAndInvertImage(self, A):
"""
:type A: List[List[int]]
:rtype: List[List[int]]
"""
return [[j^1 for j in i] for i in A]
Very clever! It use the XOR which I never mind.
Node:Related explanations are in the pycharm.
6. <Important> Flipping an Image
标签:hat style tin mod mil exp sed sans div
原文地址:https://www.cnblogs.com/sxuer/p/10629023.html