标签:des style blog http color io os ar java
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others)
Total Submission(s): 3274 Accepted Submission(s): 996
1 #include<cstdio> 2 #include<cstring> 3 #include<cmath> 4 #include<algorithm> 5 #define pi acos(-1.0) 6 #define esp 1e-8 7 using namespace std; 8 double aa[105]; 9 int main() 10 { 11 int cas,n; 12 double rr,ll; 13 scanf("%d",&cas); 14 for(int i=1;i<=cas;i++) 15 { 16 scanf("%d",&n); 17 for(int j=0;j<n;j++) 18 scanf("%lf",aa+j); 19 //确定上下边界 20 ll=20001,rr=0; 21 for(int j=0;j<n;j++) 22 { 23 rr=max(rr,aa[j]+aa[(j+1)%n]); 24 ll=min(ll,fabs(aa[j]-aa[(j+1)%n])); 25 } 26 double mid,sum,cosa; 27 printf("Case %d: ",i); 28 bool tag=0; 29 while(rr>esp+ll) 30 { 31 mid=ll+(rr-ll)/2; 32 sum=0; 33 for(int j=0;j<n;j++){ 34 //oosr=a*a+b*b-mid*mid; 余弦定理求夹角,然后判断所有的夹角之和是否为360 35 cosa=(aa[j]*aa[j]+aa[(j+1)%n]*aa[(j+1)%n]-mid*mid)/(2.0*aa[j]*aa[(j+1)%n]); 36 sum+=acos(cosa); 37 } 38 if(fabs(sum-2*pi)<esp){ 39 tag=1; 40 printf("%.3lf\n",mid); 41 break; 42 } 43 else 44 if(sum<2*pi) ll=mid; 45 else 46 rr=mid; 47 } 48 if(tag==0) 49 printf("impossible\n"); 50 } 51 return 0; 52 }
hdu 4033Regular Polygon(二分+余弦定理)
标签:des style blog http color io os ar java
原文地址:http://www.cnblogs.com/gongxijun/p/4036398.html