标签:std ble pre const 没有 sync can 链接 putc
【链接】 我是链接,点我呀:)
【题意】
题意
【题解】
先求出来强连通分量。
每个联通分量里面,显然在联通块的尽头(没有出度)放一个捕鼠夹就ok了
【代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ms(x,y) memset(x,y,sizeof x)
#define ri(x) scanf("%d",&x)
#define rl(x) scanf("%lld",&x)
#define rs(x) scanf("%s",x)
#define oi(x) printf("%d",x)
#define ol(x) printf("%lld",x)
#define oc putchar(' ')
#define os(x) printf(x)
#define all(x) x.begin(),x.end()
#define Open() freopen("F:\\rush.txt","r",stdin)
#define Close() ios::sync_with_stdio(0)
typedef pair<int,int> pii;
typedef pair<LL,LL> pll;
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
const int N = 2e5;//节点个数
vector <int> G[N+10],g[N+10];
int n,m,tot = 0,top = 0,dfn[N+10],low[N+10],z[N+10],totn,in[N+10];
int bh[N+10];
int mi[N+10];
bool bo[N+10];
int c[N+10];
int f[N+10],f_ans[N+10];
void dfs(int x){
dfn[x] = low[x] = ++ tot;
z[++top] = x;
in[x] = 1;
int len = G[x].size();
rep1(i,0,len-1){
int y = G[x][i];
if (!dfn[y]){
dfs(y);
low[x] = min(low[x],low[y]);
}else
if (in[y] && dfn[y]<low[x]){
low[x] = dfn[y];
}
}
if (low[x]==dfn[x]){
int v = 0;
totn++;
mi[totn] = c[z[top]];
while (v!=x){
v = z[top];
mi[totn] = min(mi[totn],c[v]);
in[v] = 0;
bh[v] = totn;
top--;
}
}
}
int dfs1(int x){
if (bo[x]==true) return 0;
bo[x] = true;
int len = g[x].size();
if (len==0) return mi[x];
return dfs1(g[x][0]);
}
int main(){
#ifdef LOCAL_DEFINE
freopen("rush_in.txt", "r", stdin);
#endif
ms(dfn,0);
ms(in,0);
tot = 0,totn = 0;
ri(n);
rep1(i,1,n) G[i].clear(),g[i].clear();
rep1(i,1,n){
cin >> c[i];
}
rep1(i,1,n){
int x,y;
ri(y);
x = i;
G[x].pb(y);
}
rep1(i,1,n)
if (dfn[i]==0)
dfs(i);
rep1(i,1,n){
int len = G[i].size();
int xx = bh[i];
rep1(j,0,len-1){
int y = G[i][j];
int yy = bh[y];
if (xx!=yy){
g[xx].pb(yy);
}
}
}
n = totn;
int ans = 0;
rep1(i,1,n) ans += dfs1(i);
cout<<ans<<endl;
return 0;
}
标签:std ble pre const 没有 sync can 链接 putc
原文地址:https://www.cnblogs.com/AWCXV/p/10661863.html